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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
58% (01:28) correct
42%
(01:32)
wrong
based on 189
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What are the last two digits (at tens place and units place) in the total numerical value of the following product?
243 * 8770 * 3137 * 7789 * 58263 * 3177 * 9931
A. 10
B. 30
C. 50
D. 70
E. 90
243 * 8770 * 3137 * 7789 * 58263 * 3177 * 9931
A. 10
B. 30
C. 50
D. 70
E. 90
01 Jan 2026, 09:56
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ExpertsGlobal5
Let’s consider a four digit number abcd.
If we divide the number by 100, we get abcd/100 = ab.cd
Where, cd is the last two digits.
Our given sequence is : 243 * 8770 * 3137 * 7789 * 58263 * 3177 * 9931
Since 8770 contains a zero at the unit place, we can be sure to say UNIT DIGIT = 0.
But, all options has a Zero. So cannot be used as a tool for elimination for this question.
Let’s consider the last two digits for every term in question.
43*70*37*89*63*77*31
we need to divide each term in this sequence with 100 to get the last two digits. (Look for the remainder )
= (43*70*37*89*63*77*31)/100
= (43*7*37*89*63*77*31)/10
= (3*7*7*9*3*7*1)/10
7 divided by 10 gives a remainder of 7 OR a negative remainder of -3.
so, the equation becomes
(3* -3 * -3 * -1 * 3 * -3 *1)/10
= (9*9* -3* -1* 1)/10
= 243/10
= 3/10
convert it to the base of 100, multiply numerator and denominator by 10.
30/100.
so, the last two digits is 30.
Option B
General Discussion
03 Jan 2026, 22:56
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243 * 8770 * 3137 * 7789 * 58263 * 3177 * 9931
Since I am not a pro here in formatting solutions, I will try my best to verbally represent the calculations here.
We need to understand that we need to only focus on the last two digits of the entire product. If observed with logic, this will barely take 2 mins solving in traditional multiplication format.
1. First Lets break the products, and take two individual products and will use subsequent result of each with the next value, from left to right.
2. Lets take 243 x 8770 (Reorder with larger one value x smaller value) -> 8770 x243
Now, the first value will be obviously be 0, since we multiply 3 with 0
Then, 3 x 7 will give us 21, which would allow us to keep 1 at ten's place and we get the last two digits of the first row of multiplication. We need to now check the second row, i.e. 4
Here we will have one space pushed ahead since we are multiplying ten's placed digit, so we just need to get the value of 4 x 0 which is 0.
Adding last two digits of first and second row, we have 10 from 8770 x243.
We will represent 10 as *10, since * would be the value which we are not concerned about the number.
3. Subsequently, now we multiply 3137 with *10, here the first row will be completely zero.
Next row we get 1x7 = 7. Adding last two digits of first and second row, we have 70.
4. Now 7789 x *70, here again the first row will be completely zero.
Next row we get 7x9 = 63. Taking 3. Adding last two digits of first and second row, we have 30.
5. Now, 58263 x *30, here again the first row will be completely zero.
Next row we get 3x3 = 9. Adding last two digits of first and second row, we have 90.
6. Now, 3177 x *90, here again the first row will be completely zero.
Next row we get 9x7 = 63. Adding last two digits of first and second row, we have 30.
Answer: *30
Option B
Since I am not a pro here in formatting solutions, I will try my best to verbally represent the calculations here.
We need to understand that we need to only focus on the last two digits of the entire product. If observed with logic, this will barely take 2 mins solving in traditional multiplication format.
1. First Lets break the products, and take two individual products and will use subsequent result of each with the next value, from left to right.
2. Lets take 243 x 8770 (Reorder with larger one value x smaller value) -> 8770 x243
Now, the first value will be obviously be 0, since we multiply 3 with 0
Then, 3 x 7 will give us 21, which would allow us to keep 1 at ten's place and we get the last two digits of the first row of multiplication. We need to now check the second row, i.e. 4
Here we will have one space pushed ahead since we are multiplying ten's placed digit, so we just need to get the value of 4 x 0 which is 0.
Adding last two digits of first and second row, we have 10 from 8770 x243.
We will represent 10 as *10, since * would be the value which we are not concerned about the number.
3. Subsequently, now we multiply 3137 with *10, here the first row will be completely zero.
Next row we get 1x7 = 7. Adding last two digits of first and second row, we have 70.
4. Now 7789 x *70, here again the first row will be completely zero.
Next row we get 7x9 = 63. Taking 3. Adding last two digits of first and second row, we have 30.
5. Now, 58263 x *30, here again the first row will be completely zero.
Next row we get 3x3 = 9. Adding last two digits of first and second row, we have 90.
6. Now, 3177 x *90, here again the first row will be completely zero.
Next row we get 9x7 = 63. Adding last two digits of first and second row, we have 30.
Answer: *30
Option B
