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19 May 2012, 08:56
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
41% (01:42) correct
59%
(01:56)
wrong
based on 64
sessions
History
Date
Time
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Not Attempted Yet
What will be the value of a/b ? Given that a and b are positive integers.
(1) a^2 – b^2 = 169
(2) a – b = 1
(1) a^2 – b^2 = 169
(2) a – b = 1
20 May 2012, 11:12
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What will be the value of a/b ? Given that a and b are positive integers.
(1) a^2 – b^2 = 169 --> since given that \(a\) and \(b\) are positive integers then \(a>b\). Next, \(a^2-b^2=(a-b)(a+b)=169=1*169=13*13\) --> again as \(a\) and \(b\) are positive integers and \(a>b\) then \(a-b=1\) and \(a+b=169\) --> \(a=85\) and \(b=84\) --> \(\frac{a}{b}=\frac{85}{84}\). Sufficient.
(2) a – b = 1. Clearly insufficient.
Answer: A.
(1) a^2 – b^2 = 169 --> since given that \(a\) and \(b\) are positive integers then \(a>b\). Next, \(a^2-b^2=(a-b)(a+b)=169=1*169=13*13\) --> again as \(a\) and \(b\) are positive integers and \(a>b\) then \(a-b=1\) and \(a+b=169\) --> \(a=85\) and \(b=84\) --> \(\frac{a}{b}=\frac{85}{84}\). Sufficient.
(2) a – b = 1. Clearly insufficient.
Answer: A.
Updated on: 22 May 2012, 11:01
Originally posted by vikram4689 on 22 May 2012, 09:13.
Last edited by vikram4689 on 22 May 2012, 11:01, edited 1 time in total.
Last edited by vikram4689 on 22 May 2012, 11:01, edited 1 time in total.
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Bunuel
good one... got it, but it is trickey
