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Consider a triangle which is shown here: https://www.flickr.com/photos/janmr/6163380121/
Here height will not be line from the center to vertex.
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Statement 1: Any triangle in a semicircle with the diameter as one of the sides would be a right triangle. However, this fact is not enough to find the area of the triangle. Not sufficient.

Statement 2: The triangle is isosceles only tells us that two angles of the triangle ABC are equal and nothing else. Not sufficient.

Combining: We see that triangle ABC is an isosceles right triangle. Using this we can determine that the base and height of the right triangle would be equal and we can use the value of the diameter = 2*10=20 to determine the other two sides (sides of a right isosceles triangle are in the ratio 1:1:\sqrt{2}).
Each of the other two sides would then equal 10\sqrt{2}

Area would be 05*10\sqrt{2}*10\sqrt{2}

Option C would be the answer.

hope this helps :)
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