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18 Jan 2016, 02:16
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
81% (01:06) correct
19%
(01:12)
wrong
based on 675
sessions
History
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If Mary always takes the same route to work, how long did it take Mary to get to work on Friday?
(1) It took Mary 20 minutes to get to work on Thursday.
(2) Mary's average speed on her trip to work was 25 percent greater on Thursday than it was on Friday.
(1) It took Mary 20 minutes to get to work on Thursday.
(2) Mary's average speed on her trip to work was 25 percent greater on Thursday than it was on Friday.
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18 Jan 2016, 02:21
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Either statements on their own are not suff.
Mary's speed on Thu = d/20
Mary's speed on Fri = d/t
d/20 = d/t * 1.25 --> 1/20 = 1/t * 1.25
we can calculate t. Ans C
Mary's speed on Thu = d/20
Mary's speed on Fri = d/t
d/20 = d/t * 1.25 --> 1/20 = 1/t * 1.25
we can calculate t. Ans C
15 May 2019, 06:08
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NoHalfMeasures
Target question: How long did it take Mary to get to work on Friday?
Statement 1: It took Mary 20 minutes to get to work on Thursday.
Clearly, we cannot use this information to answer the target question with certainty.
Statement 1 is NOT SUFFICIENT
Statement 2: Mary's average speed on her trip to work was 25 percent greater on Thursday than it was on Friday.
We have no information about Mary's average speed on Thursday
Statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined
Let d = the distance to work
Let s = Mary's speed on THURSDAY
Statement 1 tells us that d/s = 20 minutes
Statement 2 tells us that: (Mary's speed on Thursday) = (Mary's speed on Friday) + (25% of Mary's speed on Friday)
In other words: (Mary's speed on Thursday) = (Mary's speed on Friday) + (1/4 of Mary's speed on Friday)
In other words: (Mary's speed on Thursday) = (5/4)(Mary's speed on Friday)
Multiply both sides by 4/5 to get: (4/5)(Mary's speed on Thursday) = (Mary's speed on Friday)
Since s = Mary's speed on THURSDAY, we can see that 4s/5 = Mary's speed on Friday
So, Mary's travel TIME on Friday = distance/speed = d/(4s/5)
= (d)(5/4s)
= 5d/4s
= (5/4)(d/s)
Since we already know that d/s = 20 minutes, we can replace d/s with 20 minutes
We get: Mary's travel TIME on Friday = (5/4)(20 minutes) = 25 minutes
Since we can answer the target question with certainty, the combined statements are SUFFICIENT
Answer: C
Cheers,
Brent
