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vitaliyGMAT
siddharthsinha123
The ration r/s is expressed as a decimal. Is r/s, a terminating decimal?

(1) s = 2^3
(2) r > 0

(1) Although we have \(2^a\) in our denominator our fraction can be either a termination decimal or an integer, if s is a factor of r.

Ex. \(\frac{1}{8}\) or \(\frac{16}{8}\). Insufficient.


(2) Clearly insufficient.

(1) & (2) Again our fraction can be either a terminatig decimal: ex. \(\frac{9}{8}\) or an integer \(\frac{16}{8}\). Insufficient.

Answer E.

Hi vitaliyGMAT,

Consider the following OG question (DS 148, OG 13th Edition)

Any decimal that has only a finite number of nonzero
digits is a terminating decimal. For example, 24, 0.82,
and 5.096 are three terminating decimals.

any-decimal-that-has-only-a-finite-number-of-nonzero-digits-144328.html

I think the answer should be (A).

Thanks.
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Thank you Bunuel, I got the point.
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Hi Siddharthasinha123,

Answer should be E.

You will end up chosing answer as “A” (1 alone sufficient) if “r”considered as an integer.

So here what’s the theory is,

A fraction in its simplified form, have only 2’s or 5’s(or both) in the denominator, then it’s a terminating fraction.

Statement I is insufficient:

We don’t know whether “r” is an integer,

If r = 1/7 or 1/3, then r/s is not a terminating decimal.

If r = 2, then r/s is a terminating decimal.

Statement II is insufficient:

Nothing about “s”, that is nothing about denominator.

So not sufficient,

Together I and II also, we don’t have anything to say whether “r” is an integer.

So together also not sufficient,

So the answer is E.
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You all are stuck up in trap of question,

Actuall answer is C combination of Statment 1 and 2.

Although first Statment should have been sufficient... As per banuel explanation but we cannot assume that r and s are positive integers hence Statment one is insufficient.

Statment 2 is insufficient as only.


But from 1 and 2

R is positive integer and hence r/2^3 is terminating decimal.

Hence answer is C
Please change official answer to C

Posted from my mobile device
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You all are stuck up in trap of question,

Actuall answer is C combination of Statment 1 and 2.

Although first Statment should have been sufficient... As per banuel explanation but we cannot assume that r and s are positive integers hence Statment one is insufficient.

Statment 2 is insufficient as only.


But from 1 and 2

R is positive integer and hence r/2^3 is terminating decimal.

Hence answer is C
Please change official answer to C

Posted from my mobile device
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the question says ratio so, it cant be simplified further. r needs to be an integer here. Please correct me if i am wrong.

in my views, answer should be A.
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k9527511797
You all are stuck up in trap of question,

Actuall answer is C combination of Statment 1 and 2.

Although first Statment should have been sufficient... As per banuel explanation but we cannot assume that r and s are positive integers hence Statment one is insufficient.

Statment 2 is insufficient as only.


But from 1 and 2

R is positive integer and hence r/2^3 is terminating decimal.

Hence answer is C
Please change official answer to C

Posted from my mobile device

Statement 2 does NOT say that r is an integer. Statement 2 only tells us that r is positive. So r may be a positive integer, a positive terminating decimal, a positive non-terminating decimal, etc.

The integer assumption trap is extremely common in DS, and you fell for it here. Be sure to watch out for it, as it is often the difference between sufficient and insufficient.
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16/8=2.0 is indeed a terminating decimal...
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