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03 Jul 2017, 05:00
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
53% (02:31) correct
47%
(02:41)
wrong
based on 147
sessions
History
Date
Time
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Not Attempted Yet
The average marks obtained in a test by x students of a class was m. Was (x + 3) the average marks obtained by three students with the lowest marks in the same test?
(1) If the lowest three marks were excluded, the average score of the class would have increased by three.
(2) m = 2x.
(1) If the lowest three marks were excluded, the average score of the class would have increased by three.
(2) m = 2x.
09 Jul 2017, 07:02
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Bunuel
C ?
My understanding:
B doesnt help.
Using A:
say Sum of All/No Of Students=A/x=m
So A=mx.
Say Sum of lowest 3=L.
\frac{A-L}{x-3}=m+3
A-L=(x-3)(m+3)
A-L=mx+3x-3m-9
Use A=mx and change sides
L=3m-3x+9
L is sum of lowest 3, its average will be L/3=(3m-3x+9)/3= m-x+3
m could be anything, so Not sufficient.
Using m=2x from B,
L/3=2x-x+3=x+3
Sufficient. DS answer C.
BUT I believe if C is the answer then there might be some kind of trap making A/B/E the answer.
Couldn't find the trap.
Waiting for OA and OE by expert!
09 Jul 2017, 07:29
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C??
From 1 we can get that average marks obtained by three students with the lowest marks in the same test = (m-x)+3.
We have no Information about the relation between m&x and it may or may not be the case that m-x = x
2 doesn't help individually.
Combining 1 & 2 we get Average marks obtained by three students with the lowest marks in the same test = (m-x)+3 = (2x-x)+3 = x+3.
Hence C should be the answer.
From 1 we can get that average marks obtained by three students with the lowest marks in the same test = (m-x)+3.
We have no Information about the relation between m&x and it may or may not be the case that m-x = x
2 doesn't help individually.
Combining 1 & 2 we get Average marks obtained by three students with the lowest marks in the same test = (m-x)+3 = (2x-x)+3 = x+3.
Hence C should be the answer.
