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BrentGMATPrepNow
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BrentGMATPrepNow
If x and y are positive integers, and K equals the decimal equivalent of x/y, is K a terminating decimal?

(1) x is a divisor of 16
(2) y is a multiple of 30
Given: x and y are positive integers, and K equals the decimal equivalent of x/y

Target question: Is K a terminating decimal?

Key Property: If D = the decimal equivalent of the fraction a/b (written in simplest terms), then D will be a terminating decimal only if the prime factorization of b consists of only 2's and/or 5's
So, for example, if b = 20, the fraction a/b will result in a terminating decimal. The same holds true for other values of b such as 4, 5, 25, 40, 2, 8, and so on.


With this in mind, we can jump straight to. . .

Statements 1 and 2 combined
There are several values of x and y that satisfy BOTH statements. Here are two:
Case a: x = 48 and y = 30. In this case, K = x/y = 48/30 = 16/10 = 1.6, which means the answer to the target question is YES, K is a terminating decimal
Case b: x = 80 and y = 30. In this case, K = x/y = 80/30 = 8/3 = 2.666666...., which means the answer to the target question is NO, K is not a terminating decimal
Since we can’t answer the target question with certainty, the combined statements are NOT SUFFICIENT

Answer: E

BrentGMATPrepNow

Perhaps I am missing something, but how is \(48\) or \(80\) divisors/ factors of \(16.\)

They are actually multiples of \(16 \) rather than divisors.

After posting my solution I was wondering about the same thing.

Hope you can clarify.

Thank you.
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BrentGMATPrepNow

Perhaps I am missing something, but how is \(48\) or \(80\) divisors/ factors of \(16.\)

They are actually multiples of \(16 \) rather than divisors.

After posting my solution I was wondering about the same thing.

Hope you can clarify.

Thank you.

You're absolutely right!!!
The funny thing is I created that question a couple of weeks ago and noted the correct answer as C.
However, yesterday, when I went to post the question, I mistakenly read statement 1 as "x is a multiple of 16", and incorrectly "updated" the official answer to E.
I have edited my solution accordingly.
Thanks for the heads up!

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