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target is x even

#1
x+y= y^5
x = y(y^4-1)
if y is odd then RHS is even so x is even
if y is even then RHS is even so x is even
sufficient
#2
x+y=3y
x=2y
RHS is even so x has to be even
sufficient
option D

Bunuel
If x and y are integers, is x even?

(1) x+y=y^5

(2) x+y=3y


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From statement 1st if we put odd numbers as Y then X=even numbers and if we put even numbers as Y then also X=even, Sufficient
from statement 2nd X=2Y , any number multiply by 2 always gives even number, sufficient

[D] is the answer.
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