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Githinji
What was John’s age on 1st January, 1992?

(1) The average age of John and the five members of his family on 1st January, 1982, was equal to the average age of the five members of John’s family and a child on 1st January, 1992.

(2) The child was born on 1st January, 1992.


i find this question hard to understand. How is it possible that average of age of a group of people at one time can be equal to avaerage of age of the same group at a later date.
Regards.

John’s aga in 1982 = x
The combined age of the five members of his family in 1982 = y

The combined age of the five members of his family and a child in 1992 = y + 50 + 0

We are told that (x + y)/6 = (y + 50 + 0)/6, which gives x = 50.

Hope it helps.

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From statement (1), we have the equation:

\(\frac{J (1982) + F}{6} = \frac{F + C + 5 \times 10}{6}\)

Where:
J(1982) = John's age on 1st January, 1982
J = John's age on 1st January, 1992
F = The sum of the ages of the five members of John's family 1982
C = The age of the child on 1st January, 1992

Simplifying the equation:
\(J (1982) + F = F + C + 50\)
\(J (1982) = C + 50\)
Not Sufficent

From statement (2), we know:
\(C = 0\)
Not Sufficent

From statement (1+2):
\(J (1982) = 0 + 50 = 50\)
\(J = 60\)
Option C - Together Sufficent
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