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(1) –2< x < 2 (2) x is an integer greater than –2.
Target question:What is the value of x?
Given: x³ < x² If we do a little bit of work, we'll see that this given information tells us A LOT about x x² must be POSITIVE here (since we can see that x ≠ 0, otherwise we can't have x³ < x²). So, we can safely divide both sides of the inequality by x² to get: x < 1 So, x < 1 AND x ≠ 0
Statement 1: –2< x < 2 There are several values of x that satisfy statement 1 (and the given information). Here are two: Case a: x = -1 Case b: x = 0.5 Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: x is an integer greater than –2 So, x is an INTEGER that's less than 1, but greater than -2 AND x ≠ 0 There's only one x-value (x = -1) that satisfies these conditions. So, x must equal -1 Since we can answer the target question with certainty, statement 2 is SUFFICIENT
(1) -2<x<2 We do not know if x is an integer. If x=-1, -1 < 1(Condition satisfied) If x=-1/2, -1/8 < 1/4(Condition satisfied) Insufficient.
(2) x is an integer greater than -2 The only integer greater than -2 which satisfies the conditions is x=-1. Every other number after that does not satisfy the condition Sufficient(Option B)
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Re: What is the value of x if x^3 < x^2?
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22 Jun 2017, 17:23
1) first one is not sufficient since if I substitute 1.5, the positive number. 2)option b clearly says greater than -2;applying -1 in above condition we will get the answer.
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23 Jun 2017, 00:46
AbdurRakib wrote:
What is the value of x if \(x^3 < x^2\) ?
(1) -2<x<2
(2) x is an integer greater than -2
\(x^3 < x^2\) The above condition is possible only when x is negative For example, if x=-5 \(-125<25\) if x=-3\(-27<9\)
St1: x can have values in the range of \(-1<=x<=0\) For x= -1,-0.9,-0.8 the equation holds true No unique value NS
St2: x is int and x>-2 Then x can have only one value in this range x=-1 Since, x>0(Positive values) will not hold true; hence eliminated Suff
Option B
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28 Jun 2017, 06:50
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Top Contributor
RaguramanS wrote:
\(x^3 < x^2\) The above condition is possible only when x is negative For example, if x=-5 \(-125<25\) if x=-3\(-27<9\)
The above condition is possible only when x is negative This is not quite true. x can be any number less than 1 (but not equal to zero) For example x = 1/2 satisfies the inequality x^3 < x^2
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17 Nov 2017, 12:46
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AbdurRakib wrote:
What is the value of x if x^3 < x^2?
(1) –2< x < 2 (2) x is an integer greater than –2.
We need to determine the value of x, given that x^3 < x^2.
Statement One Alone:
–2 < x < 2
We see that x could be, for example, -1 or -½.
For either of these values, we have x^3 < x^2, since x^3 will be negative and x^2 will be positive. Since we don’t have a unique value for x, statement one alone is not sufficient.
Statement Two Alone:
x is an integer greater than –2.
We see that if x = -1, then x^3 < x^2, since x^3 = -1 and x^2 = 1.
If x = 0, then x^3 = x^2, since x^3 = 0 and x^2 = 0 (so x can’t be 0).
Similarly, if x = 1, then x^3 = x^2, since x^3 = 1 and x^2 = 1 (so x can’t be 1).
If x is an integer > 1, then x^3 will always be greater than x^2. Thus, x can’t be any integer > 1.
Therefore, we see that the only value x can be is -1. Since we have a unique value for x, statement two alone is sufficient.
Re: What is the value of x if x^3 < x^2?
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19 Nov 2017, 13:43
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1
Hi All,
We're told that X^3 is LESS than X^2. We're asked for the value of X. This question can be solved with a mix of Number Properties and TESTing VALUES.
To start, there are only certain types of values that will fit the given information that X^3 is less than X^2: -ANY negative value -Positive fractions (0 < X < 1)
1) -2 < X < 2
With Fact 1, we have LOTS of different possible values for X: any negative value and any positive fraction in that range. Fact 1 is INSUFFICIENT
2) X is an INTEGER greater than -2
The information in Fact 2 eliminates most of the possibilities that we started with. Since X has to be an INTEGER, none of the positive fractions are possible and since X has to be GREATER than -2, there's only one option possible: -1 Fact 2 is SUFFICIENT
Re: What is the value of x if x^3 < x^2?
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03 May 2018, 18:31
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Hi Mehemmed,
To start, you're treating this inequality as if it were an EQUATION - which it is NOT. The two values of X that you solved for actually do not "fit" the given inequality at all. Once you get to this point:
(X^2)(X-1)<0
You still have deal with the fact that the 'left side' of the inequality has to be be LESS than 0. Since (X^2) with either be 0 or positive, we need to focus on the other piece. With (X-1), you MUST end up with a negative.... so what values of X will make that result happen...? IF X is a positive fraction (re: 0 < X < 1) OR X is ANY negative number.
Re: What is the value of x if x^3 < x^2?
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04 May 2018, 19:15
I manipulated the inequality X^3 < X^2
X^3 - X^2 < 0 X^2 * (X-1)<0
St1: Insufficient because the values -2 and -1 satisfy. Both will result in an answer less than 0 St2: sufficient. The statement says x is greater than -2 and that it is an integer. Only -1 satisfies this statement.
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23 Aug 2018, 10:13
GMATPrepNow wrote:
AbdurRakib wrote:
What is the value of x if x³ < x²?
(1) –2< x < 2 (2) x is an integer greater than –2.
Target question:What is the value of x?
Given: x³ < x² If we do a little bit of work, we'll see that this given information tells us A LOT about x x² must be POSITIVE here (since we can see that x ≠ 0, otherwise we can't have x³ < x²). So, we can safely divide both sides of the inequality by x² to get: x < 1 So, x < 1 AND x ≠ 0
Statement 1: –2< x < 2 There are several values of x that satisfy statement 1 (and the given information). Here are two: Case a: x = -1 Case b: x = 0.5 Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: x is an integer greater than –2 So, x is an INTEGER that's less than 1, but greater than -2 AND x ≠ 0 There's only one x-value (x = -1) that satisfies these conditions. So, x must equal -1 Since we can answer the target question with certainty, statement 2 is SUFFICIENT
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19 Oct 2018, 10:31
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AbdurRakib wrote:
What is the value of x if x^3 < x^2?
(1) –2< x < 2 (2) x is an integer greater than –2.
Since \(x^3 < x^2\) is true only if x is NONZERO, we can divide by \(x^2\), which must be POSITIVE: \(\frac{x^3}{x^2} < \frac{x^2}{x^2}\) \(x < 1\) Question stem, rephrased: If x is a nonzero value less than 1, what is the value of x?
Statement 1: Here, x can be any nonzero value between -2 and 1. INSUFFICIENT.
Statement 2: Here, x must be a nonzero integer such that -2 < x < 1. Thus, x=-1. SUFFICIENT.
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