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605-655 Level|   Algebra|   Inequalities|                           
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KarishmaB
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bv8562
To Bunuel, chetan2u VeritasKarishma

Can we solve this question like this:

Given X^3 < x^2
since, the minimum value any square can have is X^2<=0
therefore, X^3<0 and it follows that x<0
Now, we have to find a specific NEGATIVE value of x from the given statements, which can ONLY be proved from the statement 2. Please let me know if this is the correct approach?

No, that will not be correct.
\(x^2>x^3………x^2(1-x)>0\)
x^2>0, so 1-x>0….x<1

Thus x can be any negative number, but x can be only between 0 and 1 when positive.

If someone says x is an integer, then surely x is negative
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bv8562
To Bunuel, chetan2u VeritasKarishma

Can we solve this question like this:

Given X^3 < x^2
since, the minimum value any square can have is X^2<=0
therefore, X^3<0 and it follows that x<0
Now, we have to find a specific NEGATIVE value of x from the given statements, which can ONLY be proved from the statement 2. Please let me know if this is the correct approach?

Hi bv8562,

While many GMATers would look at the inequality X^3 < X^2 and immediately think about negative values; since (negative)^3 = a negative and (negative)^2 = a postive - you have to be careful about assuming that these are the only possibilities. Some interesting Number Property patterns occur with positive fractions and negative fractions (re: numbers in the range of 0 < X < 1 and -1 < X < 0).

In this case of this inequality, positive fractions ALSO fit the range of acceptable values.

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bv8562
To Bunuel, chetan2u VeritasKarishma

Can we solve this question like this:

Given X^3 < x^2
since, the minimum value any square can have is X^2<=0
therefore, X^3<0 and it follows that x<0
Now, we have to find a specific NEGATIVE value of x from the given statements, which can ONLY be proved from the statement 2. Please let me know if this is the correct approach?


bv8562

Note that:

When x > 1
\(...x<x^2< x^3… \)

When 0 < x < 1
\(…x^3<x^2<x… \)

When –1 < x < 0
\(x<x^3<0<x^2… \)

When x < –1
\(x^3<x<0<x^2 \)
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Understanding that (X)^3 < (X)^2 is really “code” for saying ———-> the value of X must be a negative value or

X < 0

What’s is the value of X?

Notice that no constraint is given for X’s value.

X could be a fraction, integer, or irrational number


(1) -2 < X < 2

With the given inequality this becomes:

-2 < X < 0

X can equal any value on the number line between -2 and 0.

Not sufficient.

(2) X is a negative integer greater than -2

The only negative integer greater than -2 is ——> (-)1

Since we already know that X must be less than 0, statement 2 tells us that the only value that X can take is (-)1

S2 sufficient

B

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AbdurRakib
What is the value of x if x^3 < x^2?

(1) –2< x < 2
(2) x is an integer greater than –2.

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AbdurRakib
What is the value of x if x^3 < x^2?

(1) –2< x < 2
(2) x is an integer greater than –2.

When we are told x^3<x^2
we know that x cannot be 0
x can be either -1 or a fraction say 1/2
x cannot be negative
We need to figure the exact value of x

St 1: –2< x < 2
Here x can be neg (-1) or x can be a fraction (example 1/2)

St 2: x is an integer greater than -2
The word to focus here is x is an integer. so x cannot be 1/2 1/3 etc
so the only option that leaves us with is x=-1
Hence sufficient B
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Hey, just a quick doubt - why can't x be 0?

Thanks
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Yugank_Aggarwal
Hey, just a quick doubt - why can't x be 0?

Thanks
If x is 0, then x^3<x^2 is not valid as it will become 0^3<0^2
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