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1-(1/2-2/3)=

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Bunuel
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1-(1/2-2/3)= [#permalink] New post  24 Sep 2012, 04:59
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Quiz Dashboard Attempt only this question Same topic and source Same topic and difficulty Same source and difficulty Random Chronological Reverse chronological Learn more
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A
B
C
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E

Difficulty:

5% (low)

Question Stats:

89% (00:31) correct 11% (00:32) wrong based on 2139 sessions

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\(1-(\frac{1}{2}-\frac{2}{3})=\)

(A) 6/5
(B) 7/6
(C) 6/7
(D) 5/6
(E) 0

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Page: 158
Difficulty: 550
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Bunuel
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Re: 1-(1/2-2/3)= [#permalink] New post  24 Sep 2012, 04:59
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SOLUTION

\(1-(\frac{1}{2}-\frac{2}{3})=\)

(A) 6/5
(B) 7/6
(C) 6/7
(D) 5/6
(E) 0

\(1-(\frac{1}{2}-\frac{2}{3})=1-(\frac{3}{6}-\frac{4}{6})=1-(-\frac{1}{6})=1+\frac{1}{6}=\frac{7}{6}\).

Answer: B.
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Re: 1-(1/2-2/3)= [#permalink] New post  24 Sep 2012, 05:11
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1-(-1/6) = 7/6

Answer is B
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Re: 1-(1/2-2/3)= [#permalink] New post  24 Sep 2012, 08:36
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Here we should solve the expression within the bracket

1/2 - 2/3 = (3 - 4)/6 (by taking LCM of denominator) =-1/7

So, the overall expression becomes: 1 - (-1/7) = 1 + 1/6= 7/6

Hence B
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Re: 1-(1/2-2/3)= [#permalink] New post  24 Sep 2012, 10:16
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The answer is B but is a 300-500 level question not 600, in my opinion.

Great thread :) the OG 13th
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Re: 1-(1/2-2/3)= [#permalink] New post  24 Sep 2012, 10:27
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Bunuel wrote:
\(1-(\frac{1}{2}-\frac{2}{3})=\)

(A) 6/5
(B) 7/6
(C) 6/7
(D) 5/6
(E) 0

Practice Questions
Question: 48
Page: 158
Difficulty: 600




\(1-(\frac{1}{2}-\frac{2}{3})=1-\frac{1}{2}+\frac{2}{3}=\frac{1}{2}+\frac{2}{3}\)
The result must be greater than \(1\), so we have to choose between A and B.
Since we have two fractions with \(2\) and \(3\) in the denominator, the final result should be an improper fraction with \(6\) in the denominator.

Hence, answer B.

NB: Even without a calculator on the test, I don't think it would be a problem for anybody. I would say a below 500 level question.
I am just trying to find any type of shortcut for such questions, taking advantage of the multiple choices...really boring to simply add/subtract fractions...
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Re: 1-(1/2-2/3)= [#permalink] New post  24 Sep 2012, 10:47
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1-(-1/6)
= 1+1/6
=7/6
Ans (B)
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Bunuel
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Re: 1-(1/2-2/3)= [#permalink] New post  28 Sep 2012, 04:36
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SOLUTION

\(1-(\frac{1}{2}-\frac{2}{3})=\)

(A) 6/5
(B) 7/6
(C) 6/7
(D) 5/6
(E) 0

\(1-(\frac{1}{2}-\frac{2}{3})=1-(\frac{3}{6}-\frac{4}{6})=1-(-\frac{1}{6})=1+\frac{1}{6}=\frac{7}{6}\).

Answer: B.

Kudos points given to everyone with correct solution. Let me know if I missed someone.
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Re: 1-(1/2-2/3)= [#permalink] New post  22 Oct 2013, 14:59
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EvaJager wrote:
Bunuel wrote:
\(1-(\frac{1}{2}-\frac{2}{3})=\)

(A) 6/5
(B) 7/6
(C) 6/7
(D) 5/6
(E) 0

Practice Questions
Question: 48
Page: 158
Difficulty: 600




\(1-(\frac{1}{2}-\frac{2}{3})=1-\frac{1}{2}+\frac{2}{3}=\frac{1}{2}+\frac{2}{3}\)
The result must be greater than \(1\), so we have to choose between A and B.
Since we have two fractions with \(2\) and \(3\) in the denominator, the final result should be an improper fraction with \(6\) in the denominator.

Hence, answer B.

NB: Even without a calculator on the test, I don't think it would be a problem for anybody. I would say a below 500 level question.
I am just trying to find any type of shortcut for such questions, taking advantage of the multiple choices...really boring to simply add/subtract fractions...


Eva shortcut is to quickly get rid of 1/2 from 1 which leaves half and 1/2 and 2/3 mentions that the sum is above 1. Now we just multiply denominators look fro 6 in denominator and bingo. only one option.
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Re: 1-(1/2-2/3)= [#permalink] New post  10 Sep 2014, 09:20
Bunuel wrote:
\(1-(\frac{1}{2}-\frac{2}{3})=\)

(A) 6/5
(B) 7/6
(C) 6/7
(D) 5/6
(E) 0

Practice Questions
Question: 48
Page: 158
Difficulty: 550



(1/2-2/3) = -1/6

1-(-1/6) =7/6
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Re: 1-(1/2-2/3)= [#permalink] New post  10 Sep 2014, 10:19
1 -(1/2 -2/3)= 1 -(3-4)/6 = 1 + 1/6 =7/6
ans = B
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Re: 1-(1/2-2/3)= [#permalink] New post  10 Sep 2014, 20:02
Bunuel wrote:
\(1-(\frac{1}{2}-\frac{2}{3})=\)

(A) 6/5
(B) 7/6
(C) 6/7
(D) 5/6
(E) 0


\(1-(\frac{1}{2}-\frac{2}{3})= 1 + \frac{2}{3} - \frac{1}{2} = \frac{5}{3} - \frac{1}{2} = \frac{7}{6}\)

Answer = B
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Re: 1-(1/2-2/3)= [#permalink] New post  30 May 2016, 05:18
Expert Reply
Bunuel wrote:
\(1-(\frac{1}{2}-\frac{2}{3})=\)

(A) 6/5
(B) 7/6
(C) 6/7
(D) 5/6
(E) 0


We are given the expression 1 – (1/2 – 2/3), and we need to determine the value. We start by getting a common denominator of 6 for the fractions inside the parentheses. This gives us:

1 – (3/6 – 4/6)

1 – (–1/6) = 1 + 1/6 = 1 1/6 = 7/6

The answer is B.
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Re: 1-(1/2-2/3)= [#permalink] New post  27 Jan 2018, 07:26
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1-(1/2 - 2/3) ==> 1+(1/6) ==> 7/6
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1-(1/2-2/3)= [#permalink] New post  27 Jul 2018, 10:44
This question can be solved in the ordinary way

However, \(2/3\) > \(1/2\), therefore the expected sign is negative, when it's added to the sign outside the bracket the term become positive, so the answer should be greater than 1

(\(1/2\) - \(2/3\)) is negative because \(2/3\) > \(1/2\)
-(\(1/2\) - \(2/3\)) is positive

1 + (some +ve value)>1

if you looked on the answer choices, the only answer choice greater than 1 is B
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Re: 1-(1/2-2/3)= [#permalink] New post  16 Sep 2019, 08:02
Bunuel wrote:
\(1-(\frac{1}{2}-\frac{2}{3})=\)

(A) 6/5
(B) 7/6
(C) 6/7
(D) 5/6
(E) 0

Practice Questions
Question: 48
Page: 158
Difficulty: 550


\(1-(\frac{1}{2}-\frac{2}{3})= 1 - \frac{(3-4)}{6} = 1 +\frac{1}{6} = \frac{7}{6}\)

IMO B
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Re: 1-(1/2-2/3)= [#permalink] New post  07 Mar 2022, 13:13
1
Kudos
Hi Scott. I am sorry to bother you. I am a little bit confused. Here I was expecting to add 1 to the fraction that we found because of 1-(-1/6). I didn't seem like we had to multiply 1 by the fraction. In addition how does 1* 1/6 equal 7/6??



ScottTargetTestPrep wrote:
Bunuel wrote:
\(1-(\frac{1}{2}-\frac{2}{3})=\)

(A) 6/5
(B) 7/6
(C) 6/7
(D) 5/6
(E) 0


We are given the expression 1 – (1/2 – 2/3), and we need to determine the value. We start by getting a common denominator of 6 for the fractions inside the parentheses. This gives us:

1 – (3/6 – 4/6)

1 – (–1/6) = 1 + 1/6 = 1 1/6 = 7/6

The answer is B.
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Re: 1-(1/2-2/3)= [#permalink]
07 Mar 2022, 13:13
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