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(1/2)^(-3)*(1/4)^(-2)*(1/16)^(-1) = ?

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Updated on: 27 Sep 2014, 12:56
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Difficulty:

5% (low)

Question Stats:

89% (00:45) correct 11% (02:37) wrong based on 238 sessions

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(1/2)^(-3)*(1/4)^(-2)*(1/16)^(-1) = ?

A. 1/2^(-18)
B. 1/2^(-11)
C. 1/2^(-6)
D. 1/8^(-11)
E. 1/8^(-6)

OPEN DISCUSSION OF THIS QUESTION IS HERE: 1-144901.html

Originally posted by yezz on 12 Sep 2006, 10:38.
Last edited by Bunuel on 27 Sep 2014, 12:56, edited 2 times in total.
Renamed the topic, edited the question, added the OA and moved to PS forum.
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12 Sep 2006, 12:24
1
it's B...

(1/2)^-3 * (1/4)^-2 * (1/16)^-1 =

2^3 * 2^4 * 2^4 = 2^11 which is = 2^-11
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12 Sep 2006, 12:57
(1/2)^-3 * (1/4)^-2 * (1/16)^-1
= [(1/2)^-3] * [(1/2)^-2*2] * [(1/2)^-1*4]
= (1/2)^(-3-4-4)
= (1/2)^ -11
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12 Sep 2006, 15:57
(1/2)^-3 * (1/4)^-2 * (1/16)^-1 = ???

=[1/(1/2)^3]*[1/(1/4)^2]*[1/(1/16)]
= 8*16*16
=(2*2*2)*(2*2*2*2)*(2*2*2*2)
=2^11
=1/2^-11
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12 Sep 2006, 17:28
(1/2)^-3 * (1/4)^-2 * (1/16)^-1 = ???

(1/2)^3 = 1/(1/2)^3 which is equivalent to 1/1 * (2/1)^3 or 1*2^3

ie a/(b/c) = a/1 * c/b

then, as already stated, you are left with 2^3 * 2^4 * 2^4 = 2^11 or (1/2)^11
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27 Sep 2014, 12:56
yezz wrote:
(1/2)^(-3)*(1/4)^(-2)*(1/16)^(-1) = ?

A. 1/2^(-18)
B. 1/2^(-11)
C. 1/2^(-6)
D. 1/8^(-11)
E. 1/8^(-6)

$$(\frac{1}{2})^{-3}(\frac{1}{4})^{-2}(\frac{1}{16})^{-1}=2^3*4^2*16=2^3*2^4*2^4=2^{11}=(\frac{1}{2})^{-11}$$.

OPEN DISCUSSION OF THIS QUESTION IS HERE: 1-144901.html
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30 Aug 2018, 10:34
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: (1/2)^(-3)*(1/4)^(-2)*(1/16)^(-1) = ?   [#permalink] 30 Aug 2018, 10:34
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