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Two cars started from the same point and traveled on a straight course

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Bunuel
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Two cars started from the same point and traveled on a straight course [#permalink] New post   27 May 2019, 01:29
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Two cars started from the same point and traveled on a straight course in opposite directions for exactly 2 hours, at which time they were 208 miles apart. If one car traveled, on average, 8 miles per hour faster than the other car, what was the average speed of faster car for the 2-hour trip?

A. 32 mph
B. 40 mph
C. 48 mph
D. 56 mph
E. 64 mph
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D
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Re: Two cars started from the same point and traveled on a straight course [#permalink] New post   27 May 2019, 01:40
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Bunuel wrote:
Two cars started from the same point and traveled on a straight course in opposite directions for exactly 2 hours, at which time they were 208 miles apart. If one car traveled, on average, 8 miles per hour faster than the other car, what was the average speed of faster car for the 2-hour trip?

A. 32 mph
B. 40 mph
C. 48 mph
D. 56 mph
E. 64 mph


Let the speeds of 2 cars be v mph and v+8 mph.

Distance traveled by these cars in 2 hours is 2v and 2(v+8)

So, 2v + 2(v+8) = 208
4v = 208 - 16 = 192
v = 48 mph

Avg Speed of fast car = v + 8 = 56 mph

Option D
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Two cars started from the same point and traveled on a straight course [#permalink] New post   27 May 2019, 02:07
2v+2(v+8) = 208
4v +16 =208
4v = 192
v = 48

And v+8 = 56i have solved it like this but have a query will the average will not remain same for both the cars.isnt it the speed that we have calculated.Can you please guide Bunuel

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Re: Two cars started from the same point and traveled on a straight course [#permalink] New post   27 May 2019, 05:09
Bunuel wrote:
Two cars started from the same point and traveled on a straight course in opposite directions for exactly 2 hours, at which time they were 208 miles apart. If one car traveled, on average, 8 miles per hour faster than the other car, what was the average speed of faster car for the 2-hour trip?

A. 32 mph
B. 40 mph
C. 48 mph
D. 56 mph
E. 64 mph


speed of A = x
speed of B = x+8
distance travelled in 2 hrs
2x+2x+16=208
4x=192
x=48
speed of B; 48+8;56
IMO D
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Re: Two cars started from the same point and traveled on a straight course [#permalink] New post   25 Oct 2020, 04:27
CAR 2................................O......................................CAR 1
<....................................208....................................>
D 208 - D
S1 S2=S1+8



S2 = S1+8
(208 - D)/2 = D/2 + 8
=> (208 - D)/2 - D/2 = 8
=> (208 - 2D)/2 = 8
=> 208 - 2D = 16
=>2D = 192
=> D = 96

S1= 96/2 = 48 MILE/HOUR
S2 = 56 MILE/HOUR
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Re: Two cars started from the same point and traveled on a straight course [#permalink] New post   24 Nov 2020, 13:51
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Bunuel wrote:
Two cars started from the same point and traveled on a straight course in opposite directions for exactly 2 hours, at which time they were 208 miles apart. If one car traveled, on average, 8 miles per hour faster than the other car, what was the average speed of faster car for the 2-hour trip?

A. 32 mph
B. 40 mph
C. 48 mph
D. 56 mph
E. 64 mph


Let the speed of one car is \(s\) miles per hour

So, the speed of the faster car is \(s+8\)

\(2s+2(s+8)=208\)

\(2s+2s+16=208\)

\(4s=192\)

\(s=48\)

The speed of the faster car is \(48+8=56\)

The answer is D
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Re: Two cars started from the same point and traveled on a straight course [#permalink] New post   30 Nov 2020, 11:37
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Bunuel wrote:
Two cars started from the same point and traveled on a straight course in opposite directions for exactly 2 hours, at which time they were 208 miles apart. If one car traveled, on average, 8 miles per hour faster than the other car, what was the average speed of faster car for the 2-hour trip?

A. 32 mph
B. 40 mph
C. 48 mph
D. 56 mph
E. 64 mph

Solution:

We can let x = the average speed, in mph, of the faster car. Thus, x - 8 = the average speed of the slower car, and we can create the equation:

2(x + x - 8) = 208

2x - 8 = 104

2x = 112

x = 56

Answer: D
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Re: Two cars started from the same point and traveled on a straight course [#permalink] New post   30 Nov 2020, 12:49
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Given
    • Two cars started from the same point and traveled on a straight course in opposite directions for exactly 2 hours, at which time they were 208 miles apart.
    • One car traveled, on average, 8 miles per hour faster than the other car.


To Find

    • The average speed of the faster car for the 2-hour trip.

Approach and Working Out


    • Faster car speed = x mph, slower car = (x – 8) mph.

    • 2(x + x – 8) = 208
      o 4x = 208 + 16
      o 4x = 224
      o x = 56

Correct Answer: Option D
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Re: Two cars started from the same point and traveled on a straight course [#permalink] New post   21 Nov 2022, 23:22
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Re: Two cars started from the same point and traveled on a straight course [#permalink]
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