NEW HERE? LEARN MORE
closeclose
Last visit was: 25 Apr 2024, 14:40 It is currently 25 Apr 2024, 14:40
Decision Tracker
My Rewards
New posts
New comers' posts

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel

From the even numbers between 1 and 9, two different even numbers are

SORT BY:
Date
Kudos
Tags:
Find Similar Topics 
Show Tags
Hide Tags
User avatar
L
Bunuel
Math Expert
Joined: 02 Sep 2009
Posts: 92915
Own Kudos [?]: 619014 [0]
Given Kudos: 81595
Send PM
CAT Tests Forum Quiz Mode
From the even numbers between 1 and 9, two different even numbers are [#permalink] New post   03 Jan 2021, 11:24
Expert Reply
00:00
A
B
C
D
E

Difficulty:

55% (hard)

Question Stats:

54% (01:31) correct 46% (01:18) wrong based on 61 sessions
Hide Show timer Statistics
From the even numbers between 1 and 9, two different even numbers are to be chosen at random, without replacement. What is the probability that their sum will be 8?

A. 1/12
B. 1/6
C. 1/4
D. 1/3
E. 1/2
ShowHide Answer
Official Answer
B
User avatar
G
meanup
Senior Manager
Senior Manager
Joined: 15 Jun 2017
Posts: 388
Own Kudos [?]: 393 [4]
Given Kudos: 7
Location: India
Re: From the even numbers between 1 and 9, two different even numbers are [#permalink] New post   04 Jan 2021, 03:06
4
Kudos
Even Number between \(1\) and \(9\) are \(2,4,6,8\).

The sum of the two numbers should be \(8\), and the possible ways are \((2,6)\), or, \((6,2)\)

Probability of selecting the \(1_{st}\) number (between \(2\) or \(6\)) \(=\frac{2}{4}=\frac{1}{2}\)

Probability of selecting the \(2_{nd}\) number (between \(4,6,8\) or \(2,4,8\)) \(=\frac{1}{3}\)

The required probability \(= \frac{1}{2}∗\frac{1}{3}=\frac{1}{6}\)

IMO Ans B
User avatar
L
unraveled
CEO
CEO
Joined: 07 Mar 2019
Posts: 2554
Own Kudos [?]: 1813 [2]
Given Kudos: 763
Location: India
WE:Sales (Energy and Utilities)
Send PM
Re: From the even numbers between 1 and 9, two different even numbers are [#permalink] New post   10 Feb 2021, 00:22
1
Kudos
1
Bookmarks
Bunuel wrote:
From the even numbers between 1 and 9, two different even numbers are to be chosen at random, without replacement. What is the probability that their sum will be 8?

A. 1/12
B. 1/6
C. 1/4
D. 1/3
E. 1/2

Ways to choose two even numbers out of four(2,4,6,8) = 1st*2nd = 4*3 = 12

Even numbers that sum 8 are 2 and 6.
(4 is not possible for once 4 is choose first the other has to be 4 itself the 2nd time but it would required a replacement of 4, which is not possible AND 8 is also not possible since 0 is not available).

Ways to choose two even numbers that sum 8 = 2*1 = 2

Probability = \(\frac{2}{12} = \frac{1}{6}\)

Answer B.
User avatar
G
CEdward
VP
VP
Joined: 11 Aug 2020
Posts: 1262
Own Kudos [?]: 201 [0]
Given Kudos: 332
Send PM
Re: From the even numbers between 1 and 9, two different even numbers are [#permalink] New post   10 Feb 2021, 19:02
Rephrase the question: Given 2,4,6,8, what is the probability that their sum will be 8, if we picked the numbers without replacement? The only options are...

a) 6 + 2
b) 2 + 6

Therefore,

1/4 x 1/3 = 1/12 <--- P(picking 6 followed by 2)
1/4 x 1/3 = 1/12 <--- P(picking 2 followed by 6)

Since these are mutually exclusive events we can add:

1/12 + 1/12 = 2/12 = 1/6

Answer is B.
GMAT Club Bot
gmatclubot
Re: From the even numbers between 1 and 9, two different even numbers are [#permalink]
10 Feb 2021, 19:02
Moderators:
Bunuel
Math Expert
92915 posts
yashikaaggarwal
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne
Main navigation
GMAT Resources
Partners
MBA Resources
www.gmac.com|www.mba.com | | GMAT Club Rules | Terms and Conditions