9^(-4)/27^(-3) =

Question

\frac{9^{(-4)}}{27^{(-3)}} = 
 
A. 1/3
B. 1
C. 3
D. 9
E. 27

broall · Answer

$\frac{9^{-4}}{27^{-3}}=9^{-4}/27^{-3} = \frac{1}{9^4} / \frac{1}{27^3}=\frac{27^3}{9^4}=\frac{3^9}{3^8}=3$

The answer is C

FieryLeo · Answer

Inverting the signs.

Fraction becomes  \frac{27^3}{9^4}  =  \frac{3^9}{3^8}  = 3

LeonidK · Answer

\frac{3^{-8}}{3^{-9}} = 3^{-8-(-9)} = 3^{1} = 3

Abhishek009 · Answer

\frac{9^{(-4)}}{27^{(-3)}}

= \frac{3^{(-8)}}{3^{(-9)}}

= 3^{( 9 - 8)}

= 3^1

Thus, answer must be (C) 3

emockus · Answer

At a quick glance of the question you can easily eliminate A,D, & E because they are repeats from the question/too easily derived. That leaves B & C, inverting the fraction leaves exponents 9-8=1/base remains 3. 3^1. Answer=C.

harvardgirl1 · Answer

it is obviously 3. the answer is C.

(3^-8)/(3^-9)=3^1=3

Vinayak Shenoy · Answer

IMO C
the problem can be simplified as (27*27*27)/(9*9*9*9)= (3*3*3)/(9) = 3

9^(-4)/27^(-3) =

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9^(-4)/27^(-3) =

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