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a+b/a+b + b+c/b+c +c+a/c+a=M
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29 Aug 2019, 17:29
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38% (02:05) correct 62% (01:48) wrong based on 100 sessions
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\(\frac{a+b}{a+b} + \frac{b+c}{b+c} +\frac{c+a}{c+a}= M\) What is the difference between maximum and minimum value of M? A. 1 B. 1.5 C. 2 D. 2.5 E. 3
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a+b/a+b + b+c/b+c +c+a/c+a=M
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Updated on: 30 Aug 2019, 20:06
nick1816 wrote: \(\frac{a+b}{a+b} + \frac{b+c}{b+c} +\frac{c+a}{c+a}= M\) What is the difference between maximum and minimum value of M?
A. 1 B. 1.5 C. 2 D. 2.5 E. 3 \(\frac{a+b}{a+b} + \frac{b+c}{b+c} +\frac{c+a}{c+a}= M\) What is the difference between maximum and minimum value of M? Minimum value of the expression is 1 when a=b ; b=c; a=b=c Maximum value of expression is when a,b & c have same sign The maximum value of the expression =3 Difference = 31=2 IMO C Posted from my mobile device
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Originally posted by Kinshook on 29 Aug 2019, 18:41.
Last edited by Kinshook on 30 Aug 2019, 20:06, edited 1 time in total.



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Re: a+b/a+b + b+c/b+c +c+a/c+a=M
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30 Aug 2019, 17:39
Highlighted part is not correct. It's true only when a=b=c=0 (this case is not possible in this question) if a=b and b= c then a must be equal to c At a=b=c, M has the minimum value that is 1. Kinshook wrote: nick1816 wrote: \(\frac{a+b}{a+b} + \frac{b+c}{b+c} +\frac{c+a}{c+a}= M\) What is the difference between maximum and minimum value of M?
A. 1 B. 1.5 C. 2 D. 2.5 E. 3 \(\frac{a+b}{a+b} + \frac{b+c}{b+c} +\frac{c+a}{c+a}= M\) What is the difference between maximum and minimum value of M? Minimum value of the expression is 0 when a=b ; b=c; c= aMaximum value of expression is when a,b & c have same sign The maximum value of the expression =3 Difference = 3 IMO E Posted from my mobile device



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Re: a+b/a+b + b+c/b+c +c+a/c+a=M
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30 Aug 2019, 19:42
Hmmmmm, why can't the expresion value be equal to 0?



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Re: a+b/a+b + b+c/b+c +c+a/c+a=M
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30 Aug 2019, 20:07
Corrected. Thanks nick1816 wrote: Highlighted part is not correct. It's true only when a=b=c=0 (this case is not possible in this question) if a=b and b= c then a must be equal to c At a=b=c, M has the minimum value that is 1. Kinshook wrote: nick1816 wrote: \(\frac{a+b}{a+b} + \frac{b+c}{b+c} +\frac{c+a}{c+a}= M\) What is the difference between maximum and minimum value of M?
A. 1 B. 1.5 C. 2 D. 2.5 E. 3 \(\frac{a+b}{a+b} + \frac{b+c}{b+c} +\frac{c+a}{c+a}= M\) What is the difference between maximum and minimum value of M? Minimum value of the expression is 0 when a=b ; b=c; c= aMaximum value of expression is when a,b & c have same sign The maximum value of the expression =3 Difference = 3 IMO E Posted from my mobile device
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"Success is not final; failure is not fatal: It is the courage to continue that counts." Please provide kudos if you like my post. Kudos encourage active discussions. My GMAT Resources:  Efficient LearningAll you need to know about GMAT quantTele: +911140396815 Mobile : +919910661622 Email : kinshook.chaturvedi@gmail.com



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a+b/a+b + b+c/b+c +c+a/c+a=M
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11 Sep 2019, 20:38
No restrictions are given for values of a, b or c. so to simplify this, lets assume the value to be a =b=c = 1
we can see that, a + b = b + c = c + a = 2.... Hence all bases are same. The max. and min value totally depends on numerators now.
Maximum value can be obtained when sign of all numbers is same (we get all additions inside modulus and hence largest value). when all a, b and c all are positive or negative we will get 6 in the numerator. So the largest possible value of M would be 6/2 = 3
Smallest possible value can be obtained when one of a, b and c is having different sign while other two have same sign. (By this way there would be 2 subtractions inside modulus and 1 addition) By considering any one of a, b or c to be negative, we get 2 in the numerator. So the smallest number than can be obtained is 2/2 = 1
So the difference between largest and the smallest value is 3 1 = 2, Hence IMO (C)



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Re: a+b/a+b + b+c/b+c +c+a/c+a=M
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25 Sep 2019, 23:22
Apo_orv wrote: Hmmmmm, why can't the expresion value be equal to 0? Hi Apo_orvPlease let me know for which values of a,b or c , the expression will be 0????? Thanks



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Re: a+b/a+b + b+c/b+c +c+a/c+a=M
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28 Sep 2019, 03:55
Can somebody please help me?
I am stuck how M can be 1 at minimum. given a = b = c, the first two terms are euqal to 0, right? (a+b)/a+b = ab/a+b = a+a/a+b = a +a = 0 hence 0,
The 3th term is different : (c+a)/c+a => ca/c+a = 2a/2a = 1. So how do you get 1 as a result?



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Re: a+b/a+b + b+c/b+c +c+a/c+a=M
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28 Sep 2019, 04:44
StressTest wrote: Can somebody please help me?
I am stuck how M can be 1 at minimum. given a = b = c, the first two terms are euqal to 0, right? (a+b)/a+b = ab/a+b = a+a/a+b = a +a = 0 hence 0,
The 3th term is different : (c+a)/c+a => ca/c+a = 2a/2a = 1. So how do you get 1 as a result? Well yur resoning is incorrect for above highlighted part i would rather suggest to try some real numbers ... Hope it helps



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Re: a+b/a+b + b+c/b+c +c+a/c+a=M
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28 Sep 2019, 04:59
Rohit2015 wrote: StressTest wrote: Can somebody please help me?
I am stuck how M can be 1 at minimum. given a = b = c, the first two terms are euqal to 0, right? (a+b)/a+b = ab/a+b = a+a/a+b = a +a = 0 hence 0,
The 3th term is different : (c+a)/c+a => ca/c+a = 2a/2a = 1. So how do you get 1 as a result? Well yur resoning is incorrect for above highlighted part i would rather suggest to try some real numbers ... Hope it helps Thank you very much for the reply, but im stuck. When i set in real numbres, how would i choose them? We are saying that a = b = c So a =1, then b =1 and c =1?



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Re: a+b/a+b + b+c/b+c +c+a/c+a=M
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28 Sep 2019, 05:02
StressTest wrote: Rohit2015 wrote: StressTest wrote: Can somebody please help me?
I am stuck how M can be 1 at minimum. given a = b = c, the first two terms are euqal to 0, right? (a+b)/a+b = ab/a+b = a+a/a+b = a +a = 0 hence 0,
The 3th term is different : (c+a)/c+a => ca/c+a = 2a/2a = 1. So how do you get 1 as a result? Well yur resoning is incorrect for above highlighted part i would rather suggest to try some real numbers ... Hope it helps Thank you very much for the reply, but im stuck. When i set in real numbres, how would i choose them? We are saying that a = b = c So a =1, then b =1 and c =1? a =1, then b =1 and c =1? Yes ...u can take any...




Re: a+b/a+b + b+c/b+c +c+a/c+a=M
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