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Bunuel
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Hey,

As a,b,c,d are positive consecutive integers so a+3 will get to d and the relation between a n d is d=2a.
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Bunuel
a, b, c, and d are positive consecutive integers and a < b < c < d. If the product of b, c, and d is twice that of a, b, and c, then bc =

A. 2
B. 6
C. 12
D. 20
E. 30

a = 3
b = 4
c = 5
d = 6

b • c • d = 2 • (a • b •c)
d = 2a

bc = (4)(5) = 20

IMO Option D

Posted from my mobile device
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sanjitscorps18
1. a, b, c, and d are positive consecutive integers
2. a < b < c < d
3. bcd = 2 x abc

=> d = 2a
The four number are a, b, c, 2a

=> a + 3 = 2a
=> a = 3
hence b = 4 and c = 5

Hence bc = 20

Option D


I didn't understand how you got a+3=2a?
Saw this post today, missed it earlier.

a + 3 represents the 3rd consecutive number after a.
Since we are given consecutive (a, b, c, d) numbers to work with, we can write a + 3 = d
Also, since d = 2a we have a + 3 = 2a
Hope it's clear!!
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a, b, c, and d are positive consecutive integers and a < b < c < d. If the product of b, c, and d is twice that of a, b, and c, then bc =?

Since a, b, c, and d are positive consecutive number, we can write
b = a+1
c = a+2
d = a+3

We are given that product of b, c, and d is twice that of a, b, and c
so (a+1)(a+2)(a+3) =2 * a*(a+1)*(a+2)
after simplifying we get
a+3 = 2a
a = 3
so, b = 4 and c =5 and b*c = 20

Therefore option D is correct answer.
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