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Updated on: 23 Feb 2020, 06:24
Originally posted by ariellelouise on 23 Feb 2020, 06:19.
Last edited by Bunuel on 23 Feb 2020, 06:24, edited 1 time in total.
Last edited by Bunuel on 23 Feb 2020, 06:24, edited 1 time in total.
Renamed the topic and edited the question.
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A bag contains 3 yellow and 5 blue equally sized marbles. Two marbles are randomly removed from the bag. What is the probability that 3 yellow and 3 blue marbles remain in the bag?
(A) 1/4
(B) 5/14
(C) 1/2
(D) 5/7
(E) 5/8
(A) 1/4
(B) 5/14
(C) 1/2
(D) 5/7
(E) 5/8
23 Feb 2020, 07:26
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(B). This is a combination question.
Pick 2 from 8 without any restrictions: 8X7/2 = 28
To satisfy the requirement of 3 yellow and 3 blue after picking 2 marbles, we can only pick 2 from the 5 blue marbles: 5X4/2=10.
So the answer is: 10/28.
Pick 2 from 8 without any restrictions: 8X7/2 = 28
To satisfy the requirement of 3 yellow and 3 blue after picking 2 marbles, we can only pick 2 from the 5 blue marbles: 5X4/2=10.
So the answer is: 10/28.
23 Feb 2020, 08:11
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Quite easily done. Think about rephrasing the problem at hand, if you put your hand in the bag twice to remove 1 marble each time, what is the probability that you will remove a blue ball each time.
Hence the formula is given at:
5/8 X 4/7 = 5/14
Hence the formula is given at:
5/8 X 4/7 = 5/14
