A biologist studying the genetic code is interested to know the number of possible arrangements of 12 molecules in a chain. The chain contains 4 different molecules represented by the initials A (for adenine), C (for Cytosine), G (for Guanine) and T (for Thymine) and 3 molecules of each kind. How many different such arrangements are possible in all?


A. \(\frac{12!}{(3!)^4}\)

B. \(\frac{12!}{(4!)^3}\)

C. \(\frac{12!}{(3)^4}\)

D. \(\frac{12!}{4^3}\)

E. \(\frac{12!}{3!}\)
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