Bunuel wrote:

A circular region and a square region have the same area. What is the ratio of the side of the square to the diameter of the circle?

(A) √π/π

(B) √π/2

(C) 2/π

(D) π/4

(E) π/2

Area of square = area of circle

\(s^2 = πr^2\)

\(\sqrt{s^2}=\sqrt{π}*\sqrt{r^2}\)

\(s = \sqrt{π}*r\)

\(r = \frac{1}{2}d\), so

\(s=\sqrt{π}*r=\sqrt{π}*\frac{1}{2}d=\) \(\frac{\sqrt{π}d}{2}\)Ratio of side of square, s, to diameter, d?

\(\frac{\frac{√π(d)}{2}}{d}=\frac{√π(d)}{2d}=\frac{√π}{2}\)

Answer B

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In the depths of winter, I finally learned

that within me there lay an invincible summer.

-- Albert Camus, "Return to Tipasa"