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Re: A circular rim 28 inches in diameter rotates the same number [#permalink]
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puma wrote:
A circular rim 28 inches in a diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. If the smaller rim makes X revilutions per second, how many revilutions per minute does the larger rim makes in terms of X?

a) 48pi/x
b) 75m
c) 48x
d) 24x
e) x/75


circumference * (rev/min) of 28 =circumference * (rev/min) of 35
to calculate z
pi*28*x=pi*35*z
z=4/5 * x
but this is inch/sec we want inch/min

z=4/5 * x*60
=48x

C
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Re: A circular rim 28 inches in diameter rotates the same number [#permalink]
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let's say no. of revolution made by the larger rim = n/sec
28 *pi*x= 35*pi*n
therefore, n= (28*pi*x)/(35*pi)=4x/5
so in 1 min no of revolution = 60*(4x/5)=48x

so C
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A circular rim 28 inches in diameter rotates the same number [#permalink]
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Bunuel wrote:
A circular rim 28 inches in diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim makes in terms of x ?

A. 48pi/x
B. 75x
C. 48x
D. 24x
E. x/75

1 revolution of a circle = circumference of that circle.

1 revolution of a circle with the diameter of 28 inches = \(\pi{d}=28\pi\) inches. Hence, x revolutions per second = \(28\pi{x}\) inches per second = \(60*28\pi{x}\) inches per minute.

Given that \(60*28\pi{x}=35\pi{n}\) --> \(n=\frac{60*28\pi{x}}{35\pi}=48x\).

Answer: C.

Hope it's clear.



1 revolution of a circle with the diameter of 28 inches = \pi{d}=28\pi inches. Hence, x revolutions per second = 28\pi{x} inches per second = 60*28\pi{x} inches per minute.

Couldn't understand why 60 has come into picture?
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A circular rim 28 inches in diameter rotates the same number [#permalink]
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honchos wrote:

A circular rim 28 inches in diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim makes in terms of x ?

A. 48pi/x
B. 75x
C. 48x
D. 24x
E. x/75

1 revolution of a circle = circumference of that circle.

1 revolution of a circle with the diameter of 28 inches = \(\pi{d}=28\pi\) inches. Hence, x revolutions per second = \(28\pi{x}\) inches per second = \(60*28\pi{x}\) inches per minute.

Given that \(60*28\pi{x}=35\pi{n}\) --> \(n=\frac{60*28\pi{x}}{35\pi}=48x\).

Answer: C.

Hope it's clear.



1 revolution of a circle with the diameter of 28 inches = \pi{d}=28\pi inches. Hence, x revolutions per second = 28\pi{x} inches per second = 60*28\pi{x} inches per minute.

Couldn't understand why 60 has come into picture?[/quote]

\(28\pi{x}\) inches per second = \(60*28\pi{x}\) inches per minute.
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Re: A circular rim 28 inches in diameter rotates the same number [#permalink]
28\pi{x} inches per second = 60*28\pi{x} inches per minute.


it should be actually divided by 60 to convert it into minutes?
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Re: A circular rim 28 inches in diameter rotates the same number [#permalink]
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honchos wrote:
28\pi{x} inches per second = 60*28\pi{x} inches per minute.


it should be actually divided by 60 to convert it into minutes?


10 inches per second. There are 60 seconds in minute so 60*10 inches per minute.
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A circular rim 28 inches in diameter rotates the same number [#permalink]
Bunuel wrote:
A circular rim 28 inches in diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim makes in terms of x ?

A. 48pi/x
B. 75x
C. 48x
D. 24x
E. x/75

1 revolution of a circle = circumference of that circle.

1 revolution of a circle with the diameter of 28 inches = \(\pi{d}=28\pi\) inches. Hence, x revolutions per second = \(28\pi{x}\) inches per second = \(60*28\pi{x}\) inches per minute.

Given that \(60*28\pi{x}=35\pi{n}\) --> \(n=\frac{60*28\pi{x}}{35\pi}=48x\).

Answer: C.

Hope it's clear.


I'm still little unclear about how you equalise 60*28pi = 35pi*n
Is it because in the question it says that the inches covered by both the circles in a given time is same
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A circular rim 28 inches in diameter rotates the same number [#permalink]
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b2bt wrote:
A circular rim 28 inches in diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim makes in terms of x ?

A. 48pi/x
B. 75x
C. 48x
D. 24x
E. x/75

1 revolution of a circle = circumference of that circle.

1 revolution of a circle with the diameter of 28 inches = \(\pi{d}=28\pi\) inches. Hence, x revolutions per second = \(28\pi{x}\) inches per second = \(60*28\pi{x}\) inches per minute.

Given that \(60*28\pi{x}=35\pi{n}\) --> \(n=\frac{60*28\pi{x}}{35\pi}=48x\).

Answer: C.

Hope it's clear.


I'm still little unclear about how you equalise 60*28pi = 35pi*n
Is it because in the question it says that the inches covered by both the circles in a given time is same[/quote]

Yes.

The smaller rim = \(60*28\pi{x}\) inches per minute.
The larger rim = \(35\pi{n}\) inches per minute, where n is the number of revolution per minute.

We are told that those two are equal.

Does this make sense?
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Re: A circular rim 28 inches in diameter rotates the same number [#permalink]
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If x = 1, then the options would turn up as follows:

A. 48pi
B. 75
C. 48
D. 24
E. 1/75

Small circle circumference * 1 revolution \(= 2\pi * 14 * 1 = 28\pi\)

Large circle circumference * r revolution\(= 2\pi * 17.5 * r = 35\pi * r\)

Given that\(35\pi * r = 28\pi\)

\(r = \frac{4}{5} \frac{revolutions}{second} = \frac{4}{5} * 60 = 48 \frac{revolutions}{minute}\)

Answer = C
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Re: A circular rim 28 inches in diameter rotates the same number [#permalink]
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One important thing to keep in mind right off the bat is that the smaller rim makes x revolutions per SECOND and they ask for how many revolutions per MINUTE the larger rim makes.

If the two rims rotate the same number of inches per second, then
28(pi)x/sec=35(pi)z/sec (with z being the number of rotations the larger rim makes per second)
so we want to isolate for z and we end up with
28(pi)x/35(pi)(sec)=z/sec
the pi's cancel out and we simplify it to
4/5x however we need to multiply it by 60, because the question asks for minutes, so the answer is 48x (C)
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Re: A circular rim 28 inches in diameter rotates the same number [#permalink]
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puma wrote:
A circular rim 28 inches in diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim makes in terms of x ?

A. 48pi/x
B. 75x
C. 48x
D. 24x
E. x/75


Okay..here it goes..

Lets call the smaller one A and the larger one B.

A's diameter = \(28\), so circumference = \(28\pi\)
B's diameter = \(35\), so circumference = \(35\pi\)

Let the number of revolutions of A = x, and those of B = y.
According to the question..
\(28\pi*x = 35\pi*y\)

Thus,


\(y = \frac{4}{5}x\)

But that's the value of revolutions per second. For per minute..multiply it with 60.

Answer 48x(C).
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Re: A circular rim 28 inches in diameter rotates the same number [#permalink]
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puma wrote:
A circular rim 28 inches in diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim makes in terms of x ?

A. 48pi/x
B. 75x
C. 48x
D. 24x
E. x/75

1. We will convert x revolutions per second of the smaller rim as 60x revolutions per minute
2. The distance rotated per second is the same for both but since the diameters are different, we know that the larger rim makes lesser revolutions per second
3. The ratio of the number of revolutions of the two rims are given by the inverse of the ratio of their diameters.
4. So the number of revolutions per minute of the larger rim is 60x *(28/35) = 48x.
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Re: A circular rim 28 inches in diameter rotates the same number [#permalink]
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puma wrote:
A circular rim 28 inches in diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim makes in terms of x ?

A. 48pi/x
B. 75x
C. 48x
D. 24x
E. x/75


The smaller rim rotates at a rate of 28πx inches per second. Since the larger rim rotates the same number of inches per second, it rotates at a rate of 28πx inches per second also, and, in one minute, it rotates 28πx * 60 inches.

Since 1 rotation of the larger rim = its circumference = 35π, the number of rotations made by the larger rim will thus be:

(28πx * 60)/35π

(4x * 60)/ 5

4x * 12

48x

Answer: C
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Concept to first understand: With 1 revolution, a rim will travel the distance equal to that of its circumference. (Think about it)

Small Rim
Diameter = 28
Circumference = 28Pi
In 1 second, it makes x revolutions, so distance traveled = 28Pi(x)...........(1)

Large rim
Diameter = 35
Circumference = 35Pi
Assume in 1 second, it makes 'n' revolutions, so distance traveled = 35Pi(n)..........(2)

Now, the question says that the larger rim travels the same distance as the smaller rim per second (i.e; rotates the same number of inches). Thus, when you equate equations (1) and (2) - you get Number of revolutions by large rim (n) in terms of number of revolutions by the small rim (x) in 1 second.

35Pi(n) = 28Pi(x)
n = 4x/5 (per second)

Therefore in a minute, the larger rim makes 60n revolutions = (4x/5) * 60 = 48x

Hence the answer is C: 48x
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Re: A circular rim 28 inches in diameter rotates the same number [#permalink]
avigutman could you please explain how to Eliminate answer choices using units?
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Re: A circular rim 28 inches in diameter rotates the same number [#permalink]
Option C : 48
Simple = (28/35)*60 sec = 48 (Ratio and Proportion)
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Re: A circular rim 28 inches in diameter rotates the same number [#permalink]
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kskumar wrote:
avigutman could you please explain how to Eliminate answer choices using units?


x has units of revolutions per second, and the correct answer should have units of revolutions per minute per the question. In both cases we are looking at the following ratio:
revolutions : time
The units of answer choice A are the reciprocal of what we want (because x is in the denominator), so it can be eliminated. The other answer choices are okay as far as their units are concerned.
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