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# A function g(n), where n is an integer, is defined as the product of

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Director
Joined: 21 Dec 2009
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A function g(n), where n is an integer, is defined as the product of  [#permalink]

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22 Jan 2011, 06:30
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Difficulty:

55% (hard)

Question Stats:

52% (01:34) correct 48% (01:55) wrong based on 51 sessions

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A function g(n), where n is an integer, is defined as the product of all integers from 1 to n. How many of the followings must be a prime number?

g(11) + 5; g(11) + 6; g(11) + 7; and g(11) + 8?

A: 1
B: 2
C: 3
D: 4
E: none

How do we deduce whether g(11) + 5 or g(11) + 7 is a prime number?
I ask because others will definitely produce even number: g(11) is even;
so g(11) + 6 = even....guys, any help?

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Re: A function g(n), where n is an integer, is defined as the product of  [#permalink]

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22 Jan 2011, 07:44
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gmatbull wrote:
A function g(n), where n is an integer, is defined as the product of all integers from 1 to n.
How many of the followings must be a prime number?
g(11) + 5; g(11) + 6; g(11) + 7; and g(11) + 8?

A: 1 B: 2 C: 3 D: 4 E: none?

g(11) = product of all integers from 1 to 11
Thus g(11) is multiple of all the integers from 1 to 11.

Hence, [g(11) + any integer between 1 and 11, inclusive] is a multiple of that integer. Therefore, [g(11) + 5] is multiple of 5, [g(11) + 6] is multiple of 6 ...

Hence, none of the options are prime.

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Re: A function g(n), where n is an integer, is defined as the product of  [#permalink]

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09 Aug 2017, 11:56
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Re: A function g(n), where n is an integer, is defined as the product of   [#permalink] 09 Aug 2017, 11:56
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