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A marathoner ran for two days. On the second day he ran at an average

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A marathoner ran for two days. On the second day he ran at an average  [#permalink]

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New post 26 Sep 2018, 05:06
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E

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Question Stats:

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A marathoner ran for two days. On the second day he ran at an average speed of 3 mile per hour faster than he ran on the first day. If during the two days he ran a total of 36 miles and did a total of 8 hours running, which of the following could be his average speed, in miles per hour, on the first day?

(A) 0.25
(B) 0.50
(C) 1.00
(D) 1.50
(E) 2.00

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Re: A marathoner ran for two days. On the second day he ran at an average  [#permalink]

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New post 27 Sep 2018, 05:30
Can somebody help here
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A marathoner ran for two days. On the second day he ran at an average  [#permalink]

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New post 27 Sep 2018, 07:41
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Subhrajyoti wrote:
Can somebody help here

The easiest way is to look at the overall average. It's 36/8 = 4.5 mph.
First day's speed is x , second day's would be x+3.

If you look at option A to D , the average is >= the two elements. It not possible for the average to be higher than the two elements

Only in Option E , one element is below the average and another one is above
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Re: A marathoner ran for two days. On the second day he ran at an average  [#permalink]

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New post 27 Sep 2018, 11:47
pandeyashwin wrote:
Subhrajyoti wrote:
Can somebody help here

The easiest way is to look at the overall average. It's 36/8 = 4.5 mph.
First day's speed is x , second day's would be x+3.

If you look at option A to D , the average is >= the two elements. It not possible for the average to be higher than the two elements

Only in Option E , one element is below the average and another one is above



hi there pandeyashwin :-) if you say "It not possible for the average to be higher than the two elements" then average is is still higher than 2. pls clarify :-)
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Re: A marathoner ran for two days. On the second day he ran at an average  [#permalink]

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New post 27 Sep 2018, 11:56
dave13 wrote:
pandeyashwin wrote:
Subhrajyoti wrote:
Can somebody help here

The easiest way is to look at the overall average. It's 36/8 = 4.5 mph.
First day's speed is x , second day's would be x+3.

If you look at option A to D , the average is >= the two elements. It not possible for the average to be higher than the two elements

Only in Option E , one element is below the average and another one is above



hi there pandeyashwin :-) if you say "It not possible for the average to be higher than the two elements" then average is is still higher than 2. pls clarify :-)

The average of 1 and 4 will lie between the two extremes. It cannot be higher than 4 or lower than 1
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Re: A marathoner ran for two days. On the second day he ran at an average  [#permalink]

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New post 02 Oct 2018, 19:35
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Bunuel wrote:
A marathoner ran for two days. On the second day he ran at an average speed of 3 mile per hour faster than he ran on the first day. If during the two days he ran a total of 36 miles and did a total of 8 hours running, which of the following could be his average speed, in miles per hour, on the first day?

(A) 0.25
(B) 0.50
(C) 1.00
(D) 1.50
(E) 2.00


The average speed for the entire two days was 36/8 = 4.5 mph

Thus, since the speed on the first day was 3 mph slower than that of the second day, the speed on the first day must be less than 4.5 mph and the speed on the second day must be greater than 4.5 mph.

Since the speed on the second day is greater than 4.5 mph, which is 3 mph faster than that of the first day, the speed on the first day must be greater than 1.5 mph. So the only possible speed on the first day, from the given answer choices, is 2 mph.

Answer: E
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A marathoner ran for two days. On the second day he ran at an average  [#permalink]

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New post 14 Feb 2019, 06:40
Can someone please help in understanding the concepts with this one? I am getting r=3 but then from there I am having trouble determining that the first day is 2.00.

Any help would be appreciated! :)


Khow

Bunuel wrote:
A marathoner ran for two days. On the second day he ran at an average speed of 3 mile per hour faster than he ran on the first day. If during the two days he ran a total of 36 miles and did a total of 8 hours running, which of the following could be his average speed, in miles per hour, on the first day?

(A) 0.25
(B) 0.50
(C) 1.00
(D) 1.50
(E) 2.00
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A marathoner ran for two days. On the second day he ran at an average  [#permalink]

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New post 21 May 2019, 07:59
KHow wrote:
Can someone please help in understanding the concepts with this one? I am getting r=3 but then from there I am having trouble determining that the first day is 2.00.

Any help would be appreciated! :)


Khow

Bunuel wrote:
A marathoner ran for two days. On the second day he ran at an average speed of 3 mile per hour faster than he ran on the first day. If during the two days he ran a total of 36 miles and did a total of 8 hours running, which of the following could be his average speed, in miles per hour, on the first day?

(A) 0.25
(B) 0.50
(C) 1.00
(D) 1.50
(E) 2.00



I followed the below approach:

Total distance travelled = 36miles
Let the avg speed on day 1 be x m/hr
=> avg speed on day 2 = (x+3) m/hr

Let the time taken on day 1 be t, hence the time taken on day 2 = (8-t)

applying the simple s*t =d formula

xt + (x+3)(8-t) = 36
=> xt + 8x - xt + 24 - 3t = 36
=> 8x - 3t = 12

Now, from the options, only the value 2 satisfies the above equation as for x = 1.5 m/hr, 't' (for day 1) will have to be equal to 0 which is not the case.
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A marathoner ran for two days. On the second day he ran at an average   [#permalink] 21 May 2019, 07:59
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