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sumi747

I am still not clear with the explanation as to how p would be only 5 and nothing greater than it. Could you try elaborating?

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Hey sumi747,

Because if you had a different prime factor, there would be more than 4 positive factors total.
For example, say 7 was a factor.
Since 25 is a factor, then 7*25=175 is also a factor, and so are 5*7=35 and 7.
So N must have 1,5,25,7,35,175 as factors, meaning it has more than 4 unique factors, a contradiction.
In general, for any prime p other than 5, you will have 1,5,25,p,5p,25p so at least 6 factors. Then the only prime factor of N is 5.
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St.1:
2x5= 10, highest PF= 5
5x7= 35, highest PF= 7
And so on
Insufficient.

Caution: Do not carry out thoughts from Statement 1 to Statement 2.

St.2:
5^2 is a factor of N.
And total factors of N is 4.

In this case, if another PF besides 5 is a part of N, then min total factors of N will become (2+1)*(1+1)= 3*2= 6.

So, for N to have 4 factors, value of N should be 5^3.
Highest PF is 5.
Sufficient

Ans B
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