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A product designer is trying to design the largest container possible

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A product designer is trying to design the largest container possible  [#permalink]

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New post 31 Oct 2010, 07:25
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A product designer is trying to design the largest container possible hat will fit into a 6x12x14 box. Because of constraints in the manufacturing process, he must make the container in the shape of a cylinder, which will then be placed base down inside the box. What is the volume of the largest cylinder that can fit in the box?

A) 108π
B) 126π
C) 216π
D) 504π
E) 864π
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Re: A product designer is trying to design the largest container possible  [#permalink]

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New post 31 Oct 2010, 10:21
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Jumphi97 wrote:
A product designer is trying to design the largest container possible hat will fit into a 6x12x14 box. Because of constraints in the manufacturing process, he must make the container in the shape of a cylinder, which will then be placed base down inside the box. What is the volume of the largest cylinder that can fit in the box?

A) 108π
B) 126π
C) 216π
D) 504π
E) 864π


Volume of a cylinder is \(\pi r^2 h\)
There is 3 configurations possible :
Height along side 6 --> Base on area of 12x14 --> Max radius is 6 : Vol = \(216 \pi\)
Hieght along side 12 --> Base on area of 6x14 --> Max radius is 3 : Vol = \(108 \pi\)
Height along side 14 --> Base on area of 6x12 --> Max radius is 3 : Vol = \(126 \pi\)

So max volume possible is (C)
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Re: A product designer is trying to design the largest container possible  [#permalink]

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New post 31 Oct 2010, 10:34
Volume of a cylinder = \(\pi r^2 h\)

Since the cylinder is placed into the box base down, we have two options for the base of the cylinder: 6 or 12. For whichever two numbers we choose as the base of the box, the diameter of the cylinder has to be equal to the lesser of the two dimensions in order to fit.

Our goal is to maximize the volume of the cylinder, which means we want the largest possible base. This is because \(r^2\) will create a larger number than \(h\).

The base of the box would therefore be 12x14 with a height of 6. This allows for the following dimensions of the cylinder:

\(\pi 12^2 * 6\) = \(216\pi\)
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Re: A product designer is trying to design the largest container possible  [#permalink]

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New post 31 Oct 2010, 10:42
Jumphi97 wrote:
A product designer is trying to design the largest container possible hat will fit into a 6x12x14 box. Because of constraints in the manufacturing process, he must make the container in the shape of a cylinder, which will then be placed base down inside the box. What is the volume of the largest cylinder that can fit in the box?

A) 108π
B) 126π
C) 216π
D) 504π
E) 864π


Check similar question for practice: problem-solving-100223.html#p772770
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Re: A product designer is trying to design the largest container possible  [#permalink]

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New post 31 Oct 2010, 18:59
volume of cylinder = pi * r^2 * h
as r has more power,we have to maximixe r. --- A

also we know that for a rectangular base, diameter can not be more than the smaller side...B

from A, B, we know r will me maximum when the base is 12 * 14 and r will be 12/2 = 6

so volume will be pi * 6^2 * 6 = 216pi ...option C
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A product designer is trying to design the largest container possible  [#permalink]

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New post 26 Sep 2018, 01:39
Jumphi97 wrote:
A product designer is trying to design the largest container possible hat will fit into a 6x12x14 box. Because of constraints in the manufacturing process, he must make the container in the shape of a cylinder, which will then be placed base down inside the box. What is the volume of the largest cylinder that can fit in the box?

A) 108π
B) 126π
C) 216π
D) 504π
E) 864π


OA: C

Case 1: Base Dimensions \(=6*12\); Height \(= 14\)

then radius of cylinder will be \(\frac{6}{2}=3\) and height will be \(14\)

Volume \(= \pi r^2h =\pi *3^2*14=126\pi\)

Case 2: Base Dimensions \(=6*14\); Height \(= 12\)

then radius of cylinder will be \(\frac{6}{2}=3\) and height will be \(12\)

Volume \(= \pi r^2h =\pi *3^2*12=108\pi\)

Case 3: Base Dimensions \(=14*12\); Height \(= 6\)

then radius of cylinder will be \(\frac{12}{2}=6\) and height will be \(6\)

Volume \(= \pi r^2h = \pi *6^2*6=216\pi\)(Largest Cyclinder)
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Re: A product designer is trying to design the largest container possible  [#permalink]

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New post 27 Sep 2018, 02:22
quick solve:
it says box (which has 3 different sides) => meaning it's a cuboid. Then, compute the volume of the cuboid (14*12*6=1008).
Now try to fit one of the 5 volumes of the cylinder into the 1008cm3 of the cuboid.
You'll realize option c) 216*pi which is more or less 216*3=648cm3 is the max you can fit into the cuboid.
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Re: A product designer is trying to design the largest container possible &nbs [#permalink] 27 Sep 2018, 02:22
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