EBITDA wrote:

Here is my go:

Surface Cylinder = 2 π r^2 + 2 π r * 2 r = 2 π r^2 + 4 π r^2 = 6 π r^2

Surface Cube = 6 π r^2

To get one length of the cube:

6 x^2 = 6 π r^2 ; x^2 = π r^2 ; x = r \(\sqrt{π}\)

Volume Cylinder = π r^2 * 2r = 2 π r^3

Volume Cube = x^3 = (r \(\sqrt{π}\))^3 = r^3 π \(\sqrt{π}\)

Volume Cylinder/Volume Cube = (2 π r^3) / (r^3 π \(\sqrt{π}\))

= (2/\(\sqrt{π}\)) * (\(\sqrt{π}\)/\(\sqrt{π}\))

= (2*\(\sqrt{π}\))) / π

Roughly, this is:

2 * 1.75 / 3.15 = 3.50 / 3.15

Which is between 10% and 15% more.

Please let me know if there is any error in this thought process.

How do you know if it is total surface area or lateral surface area?

_________________

My GMAT Story: From V21 to V40

My MBA Journey: My 10 years long MBA Dream

My Secret Hacks: Best way to use GMATClub | Importance of an Error Log!

Verbal Resources: All SC Resources at one place | All CR Resources at one place

Blog: Subscribe to Question of the Day Blog

GMAT Club Inbuilt Error Log Functionality - View More.

New Visa Forum - Ask all your Visa Related Questions - here.

New! Best Reply Functionality on GMAT Club!

Find a bug in the new email templates and get rewarded with

2 weeks of GMATClub Tests for free