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# A simple PS..

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Manager
Joined: 04 Sep 2007
Posts: 205

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28 Jul 2008, 15:39
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Question Stats:

100% (00:00) correct 0% (00:00) wrong based on 9 sessions

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I am wondering what is the prescribed method for solving this problem - Sets??

Last year, 36 houses in a certain development had roof repairs and 48 houses were repainted. If 20 houses in the development had roof repairs but were not repainted last year, how many houses were repainted but did not have roof repairs?

A. 12
B. 16
C. 20
D. 28
E. 32

I chose "E" but am not sure if I am correct. FYI, I do not know the OA as well the source. Thanks.

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SVP
Joined: 30 Apr 2008
Posts: 1841
Location: Oklahoma City
Schools: Hard Knocks

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28 Jul 2008, 16:06
This question doesn't make much sense if the answer is not 32. I used a Venn Diagram for this and came up with 32 also.

It just makes sense that of the 36 houses, they either were or were not also repainted. So if we know 20is the number that were not repainted, that leaves 16 that were also repainted. So 16 of the repainted houses also had roof repairs, then 48 - 16 = the number of houses that were repainted but did not have roof repairs. This should be 32.

wizardofwashington wrote:
I am wondering what is the prescribed method for solving this problem - Sets??

Last year, 36 houses in a certain development had roof repairs and 48 houses were repainted. If 20 houses in the development had roof repairs but were not repainted last year, how many houses were repainted but did not have roof repairs?

A. 12
B. 16
C. 20
D. 28
E. 32

I chose "E" but am not sure if I am correct. FYI, I do not know the OA as well the source. Thanks.

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J Allen Morris
**I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a\$\$.

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Manager
Joined: 04 Sep 2007
Posts: 205

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28 Jul 2008, 19:08
Thanks, jallenmorris. I am glad that we are on the same page.
A

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Re: A simple PS.. &nbs [#permalink] 28 Jul 2008, 19:08
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