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A square and an equilateral triangle have perimeters S and T respectiv

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A square and an equilateral triangle have perimeters S and T respectiv [#permalink]

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New post 27 Sep 2017, 04:51
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A square and an equilateral triangle have perimeters S and T respectively. If s and t are the respective lengths of a side of the square and a side of the triangle, then, in terms of their perimeters, s – t =

(A) (S – T)/7
(B) (4T – 3S)/7
(C) (3S – 4T)/7
(D) (4T – 3S)/12
(E) (3S – 4T)/12
[Reveal] Spoiler: OA

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Kudos [?]: 128565 [0], given: 12180

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Joined: 29 Aug 2017
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A square and an equilateral triangle have perimeters S and T respectiv [#permalink]

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New post 27 Sep 2017, 06:07
Bunuel wrote:
A square and an equilateral triangle have perimeters S and T respectively. If s and t are the respective lengths of a side of the square and a side of the triangle, then, in terms of their perimeters, s – t =

(A) (S – T)/7
(B) (4T – 3S)/7
(C) (3S – 4T)/7
(D) (4T – 3S)/12
(E) (3S – 4T)/12


Perimeter of square = S
Side of square = s = S/4
Perimeter of equilateral triangle = T
Side of equilateral triangle = t = T/3
s - t \(= \frac{S}{4}- \frac{T}{3} = \frac{(3S - 4T)}{12}\)

Therefore, answer is E.

Kudos [?]: 1 [0], given: 28

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Re: A square and an equilateral triangle have perimeters S and T respectiv [#permalink]

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New post 29 Sep 2017, 11:21
Bunuel wrote:
A square and an equilateral triangle have perimeters S and T respectively. If s and t are the respective lengths of a side of the square and a side of the triangle, then, in terms of their perimeters, s – t =

(A) (S – T)/7
(B) (4T – 3S)/7
(C) (3S – 4T)/7
(D) (4T – 3S)/12
(E) (3S – 4T)/12


Since the square has a perimeter of S, its side length s = S/4. Similarly, since the equilateral triangle has a perimeter of T, its side length t = T/3. Thus, s - t = S/4 - T/3 = 3S/12 - 4T/12 = (3S - 4T)/12.

Answer: E
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Kudos [?]: 827 [0], given: 5

Re: A square and an equilateral triangle have perimeters S and T respectiv   [#permalink] 29 Sep 2017, 11:21
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