Last visit was: 25 Apr 2024, 02:33 It is currently 25 Apr 2024, 02:33

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Tags:
Show Tags
Hide Tags
Math Expert
Joined: 02 Sep 2009
Posts: 92912
Own Kudos [?]: 618885 [5]
Given Kudos: 81595
Send PM
GMAT Club Legend
GMAT Club Legend
Joined: 18 Aug 2017
Status:You learn more from failure than from success.
Posts: 8019
Own Kudos [?]: 4096 [0]
Given Kudos: 242
Location: India
Concentration: Sustainability, Marketing
GMAT Focus 1:
545 Q79 V79 DI73
GPA: 4
WE:Marketing (Energy and Utilities)
Send PM
GMAT Club Legend
GMAT Club Legend
Joined: 03 Oct 2013
Affiliations: CrackVerbal
Posts: 4946
Own Kudos [?]: 7626 [2]
Given Kudos: 215
Location: India
Send PM
Manager
Manager
Joined: 17 Jul 2017
Posts: 205
Own Kudos [?]: 93 [0]
Given Kudos: 228
Send PM
A star-polygon is drawn on a clock face by drawing a chord from each [#permalink]
ArvindCrackVerbal wrote:
Now, although at first, this question can look difficult and overwhelming, as you plot the figure, you will observe that there are more than 1 ways of answering this question.

This might not exactly be a GMAT type of question because Star polygons are non-convex polygons and GMAT does not test you on non-convex polygons. However, this is definitely a good question to test out your knowledge of circle concepts.

From the description of the polygon given in the question, this looks like a self-intersecting regular star polygon, since the length of each side is the same.
A self-intersecting regular star polygon is an equiangular polygon. So, all the angles of this polygon will be equal.

Let us draw the polygon now:

Attachment:
2nd Aug 2019 - Reply 1 - 2.JPG


Looks brilliant, isn't it?
ArvindCrackVerbal
please clear mey doubt
total sum of angles =(n-2)*180
s0 12-2*180=1800
now each interior angle=1800/12=150
where m i going wrong

As mentioned by Archit in his reply, we see that the polygon obtained is a 12 sided polygon. Since the method involving the sum of the interior angles is already discussed, let’s look at another way of solving this question.

This method is based on the angle made by the arcs touched by the sides of the polygon. To make things clearer, here’s another diagram, showing only the first 2 sides of the polygon.

Attachment:
2nd Aug 2019 - Reply 1 - 1.JPG


Clearly, the angle made by arc 10-11-12 at the centre is 60 degrees, since each arc on a clock corresponds to an angle of 30 degrees. Since the arc 10-11-12 makes 60 degree at the centre, it will make exactly half i.e. 30 degrees at any point on the circumference.

This is precisely the angle that we were looking for. So, the interior angle of this polygon is 30 degrees.
The correct answer option is C.

Hope this helps!



ArvindCrackVerbal
please clear mey doubt
total sum of angles =(n-2)*180
s0 12-2*180=1800
now each interior angle=1800/12=150
where m i going wrong
GMAT Club Bot
A star-polygon is drawn on a clock face by drawing a chord from each [#permalink]
Moderators:
Math Expert
92912 posts
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne