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08 Dec 2014, 06:19
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E
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Difficulty:
15%
(low)
Question Stats:
80% (01:18) correct
20%
(01:38)
wrong
based on 209
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A student is to take her final exams in three subjects. The probability that she will pass the first subject is 3/4, the probability that she will pass the second subject is 2/3, and the probability that she will pass the third subject is 1/2. What is the probability that she will pass at least one of these three exams?
A) 1/4
B) 11/24
C) 17/24
D) 3/4
E) 23/24
Source: Chili Hot GMAT
A) 1/4
B) 11/24
C) 17/24
D) 3/4
E) 23/24
Source: Chili Hot GMAT
08 Dec 2014, 10:45
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Bunuel
Probability that she will pass in at least one exam = 1- probability that she will fail in all three of her exams.
= 1- \(\frac{1}{4}.\frac{1}{3}.\frac{1}{2}\)
= \(\frac{23}{24}\)
hence E
08 Dec 2014, 10:52
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probability of passing at least one = 1 - probability of passing none (or probability of not passing first subject AND not passing second subject AND not passing third subject, so we will have to multiply)
probability of not passing first subject = 1 - (3/4) = 1/4
probability of not passing second subject = 1 - (2/3) = 1/3
probability of not passing third subject = 1 - (1/2) = 1/2
probability of not passing any subjects = (1/4) x (1/3) x (1/2) = 1/24
probability of passing at least one subject = 1 - (1/24) = 23/24
Answer E!
probability of not passing first subject = 1 - (3/4) = 1/4
probability of not passing second subject = 1 - (2/3) = 1/3
probability of not passing third subject = 1 - (1/2) = 1/2
probability of not passing any subjects = (1/4) x (1/3) x (1/2) = 1/24
probability of passing at least one subject = 1 - (1/24) = 23/24
Answer E!
