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# A train trip begins at Lawrenceville, makes stops first at Milton and

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Manager
Joined: 20 Nov 2009
Posts: 127
A train trip begins at Lawrenceville, makes stops first at Milton and  [#permalink]

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26 Jul 2010, 21:47
00:00

Difficulty:

(N/A)

Question Stats:

100% (08:11) correct 0% (00:00) wrong based on 8 sessions

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A train trip begins at Lawrenceville, makes stops first at Milton and then at Overton, and ends at Pottstown. The distance between Lawrenceville and Overton is four times the distance between Overton and Pottstown, and the distance between Lawrenceville and Milton is equal to half the distance between Milton and Overton. The trip from Lawrenceville to Overton is how many times the trip from Milton to Pottstown?
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Joined: 20 Mar 2010
Posts: 78
Re: A train trip begins at Lawrenceville, makes stops first at Milton and  [#permalink]

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26 Jul 2010, 22:22
aiming4mba wrote:
A train trip begins at Lawrenceville, makes stops first at Milton and then at Overton, and ends at Pottstown. The distance between Lawrenceville and Overton is four times the distance between Overton and Pottstown, and the distance between Lawrenceville and Milton is equal to half the distance between Milton and Overton. The trip from Lawrenceville to Overton is how many times the trip from Milton to Pottstown?

L------M--------O--------P

LO= 4 OP
LM = (1/2)* MO

LO= x(MP) x=?

LO= LM+MO
4OP= (1/2)*MO+ MO = (3/2)*MO ==> MO= (8/3)* OP

LO= x(MP)=x(MO+OP)
4OP=x(MO+OP)
4OP=x((8/3)*OP +OP) ===> x = 12/11
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Re: A train trip begins at Lawrenceville, makes stops first at Milton and  [#permalink]

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27 Jul 2010, 00:36
In my openion it will be 11/12. Please correct me if i am wrong.
Thanks
Intern
Joined: 16 Jul 2010
Posts: 2
Re: A train trip begins at Lawrenceville, makes stops first at Milton and  [#permalink]

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31 Jul 2010, 14:13
I would go with 12/11
Manager
Joined: 16 Mar 2010
Posts: 143
Re: A train trip begins at Lawrenceville, makes stops first at Milton and  [#permalink]

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07 Sep 2010, 00:26
Yes my mistake, its is 12/11
Director
Joined: 27 May 2012
Posts: 631
Re: A train trip begins at Lawrenceville, makes stops first at Milton and  [#permalink]

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29 Oct 2017, 05:02
1
1
aiming4mba wrote:
A train trip begins at Lawrenceville, makes stops first at Milton and then at Overton, and ends at Pottstown. The distance between Lawrenceville and Overton is four times the distance between Overton and Pottstown, and the distance between Lawrenceville and Milton is equal to half the distance between Milton and Overton. The trip from Lawrenceville to Overton is how many times the trip from Milton to Pottstown?

Old question , but I am getting 4/3
Can anybody point out my mistake ? or whether I am correct. Thank you.
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- Stne

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Joined: 22 May 2016
Posts: 2207
A train trip begins at Lawrenceville, makes stops first at Milton and  [#permalink]

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30 Oct 2017, 11:50
1
stne wrote:
aiming4mba wrote:
A train trip begins at Lawrenceville, makes stops first at Milton and then at Overton, and ends at Pottstown. The distance between Lawrenceville and Overton is four times the distance between Overton and Pottstown, and the distance between Lawrenceville and Milton is equal to half the distance between Milton and Overton. The trip from Lawrenceville to Overton is how many times the trip from Milton to Pottstown?

Old question , but I am getting 4/3
Can anybody point out my mistake ? or whether I am correct. Thank you.

stne , you didn't show your math, so I'm not quite sure where you might have gone wrong.

Because the "four times" seemed like a big pain, I picked this part first:
Quote:
the distance between Lawrenceville and Milton is equal to half the distance between Milton and Overton

I assigned $$x$$ to the distance between M and O, then $$\frac{1}{2}x$$ for L to M

L---$$\frac{1}{2}x$$---M------$$x$$------O-------P

Then
Quote:
The distance between L.. and O.. is four times the distance between O.. and P..

Distance between L and O =
$$\frac{1}{2}x + x =\frac{3}{2}x$$
-- which is four times the distance between O and P:

$$\frac{(\frac{3}{2}x)}{4}=\frac{3}{8}x$$

L----$$\frac{1}{2}x$$----M------$$x$$------O---$$\frac{3}{8}x$$---P

Finally, L to O is how many times the distance from M to P?

We know L to O = $$\frac{3}{2}x$$

M to P? $$x + \frac{3}{8}x=\frac{11}{8}x$$

How many times?

$$\frac{(\frac{3}{2}x)}{(\frac{11}{8}x)}=\frac{(\frac{12}{8}x)}{(\frac{11}{8}x)}=\frac{12}{11}$$

Answer: $$\frac{12}{11}$$ times

I have a feeling you might have started with:
O to P = x
L to O = 4x

It will still work. Maybe draw it in parts, as here?

Hope that helps.
A train trip begins at Lawrenceville, makes stops first at Milton and &nbs [#permalink] 30 Oct 2017, 11:50
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