stne wrote:

aiming4mba wrote:

A train trip begins at Lawrenceville, makes stops first at Milton and then at Overton, and ends at Pottstown. The distance between Lawrenceville and Overton is four times the distance between Overton and Pottstown, and the distance between Lawrenceville and Milton is equal to half the distance between Milton and Overton. The trip from Lawrenceville to Overton is how many times the trip from Milton to Pottstown?

Old question , but I am getting 4/3

Can anybody point out my mistake ? or whether I am correct. Thank you.

stne , you didn't show your math, so I'm not quite sure where you might have gone wrong.

Because the "four times" seemed like a big pain, I picked this part first:

**Quote:**

the distance between Lawrenceville and Milton is equal to half the distance between Milton and Overton

I assigned \(x\) to the distance between M and O, then \(\frac{1}{2}x\) for L to M

L---\(\frac{1}{2}x\)---M------\(x\)------O-------P

Then

**Quote:**

The distance between L.. and O.. is four times the distance between O.. and P..

Distance between L and O =

\(\frac{1}{2}x

+ x =\frac{3}{2}x\)

-- which is four times the distance between O and P:

\(\frac{(\frac{3}{2}x)}{4}=\frac{3}{8}x\)

L----\(\frac{1}{2}x\)----M------\(x\)------O---\(\frac{3}{8}x\)---P

Finally, L to O is how many times the distance from M to P?

We know L to O = \(\frac{3}{2}x\)

M to P? \(x +

\frac{3}{8}x=\frac{11}{8}x\)

How many times?

\(\frac{(\frac{3}{2}x)}{(\frac{11}{8}x)}=\frac{(\frac{12}{8}x)}{(\frac{11}{8}x)}=\frac{12}{11}\)

Answer: \(\frac{12}{11}\) times

I have a feeling you might have started with:

O to P = x

L to O = 4x

It will still work. Maybe draw it in parts, as here?

Hope that helps.