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# Another Exponent Problem

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Current Student
Joined: 03 Dec 2007
Posts: 82
Schools: NYU STERN
Another Exponent Problem [#permalink]

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04 Feb 2009, 18:24
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Which is equal to (2^k)[5^(k-1)]?

a) 2[10^(k-1)]
b) 5[10^(k-1)]
c) $$10^k$$
d) $$2(10^k)$$
e) 10^(2k-1)
GMAT Tutor
Joined: 24 Jun 2008
Posts: 1346
Re: Another Exponent Problem [#permalink]

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04 Feb 2009, 20:30
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Expert's post
hardaway7 wrote:
Which is equal to (2^k)[5^(k-1)]?

a) 2[10^(k-1)]
b) 5[10^(k-1)]
c) $$10^k$$
d) $$2(10^k)$$
e) 10^(2k-1)

$$2^k \times 5^{k-1} = 2 \times 2^{k-1} \times 5^{k-1} = 2 \times 10^{k-1}$$
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Current Student
Joined: 03 Dec 2007
Posts: 82
Schools: NYU STERN
Re: Another Exponent Problem [#permalink]

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04 Feb 2009, 21:10
Perfect - THANKS!!!
Re: Another Exponent Problem   [#permalink] 04 Feb 2009, 21:10
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# Another Exponent Problem

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