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At a certain pet shop, 1/3 of the pets are dogs and 1/5 of
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17 Jul 2010, 09:29
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At a certain pet shop, 1/3 of the pets are dogs and 1/5 of the pets are birds. How many of the pets are dogs? (1) There are 30 birds at the pet shop. (2) There are 20 more dogs than birds at the pet shop. Can't understand how to get the answer from (2). Do we consider that dogs and pets are only animals in the shop?
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Re: Pets from the shop (mba.com)
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18 Nov 2010, 19:05
ulm wrote: Can't understand how to get the answer from (2) Do we consider that dogs and pets are only animals in the shop? To answer your question, no we do not consider that dogs and birds are the only animals at the shop. In fact, we know they are not because \(\frac{1}{3} + \frac{1}{5} = \frac{8}{15}\). So dogs and birds account for only 8/15th of the total animals. Now, let's solve this question using ratios. Dogs : Birds = \(\frac{1}{3} : \frac{1}{5}\). Multiply this ratio by 15 to convert it into integers. Remember, when you multiply the entire ratio by the same number, the ratio remains the same. Dogs : Birds = 5:3. For every 3 birds, there are 5 dogs. Stmnt 1: If birds are 30, dogs will be 50. Sufficient. Stmnt 2: The difference in number of dogs are birds in ratio terms is 2 (because 5  3 = 2), but is actually 20. So 5 will correspond to 50. Sufficient. Ratios are a great way to quickly and easily solve questions. If this method is not clear, give me a couple of days. I will put up a blog explaining it in detail.
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Re: Pets from the shop (mba.com)
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17 Jul 2010, 10:19
ulm wrote: Can't understand how to get the answer from (2). Do we consider that dogs and pets are only animals in the shop? Not so. We are told that \(\frac{1}{3}\) of the pets are dogs and \(\frac{1}{5}\) of the pets are birds > \(\frac{1}{3}+\frac{1}{5}=\frac{8}{15}<1=total\). At a certain pet shop, 1/3 of the pets are dogs and 1/5 of the pets are birds. How many of the pets are dogs? (1) There are 30 birds at the shop > \(\frac{1}{5}\) of the pets are birds > \(\frac{1}{5}t=30\), where \(t\) is the # of pets at the pet shop > \(t=150\) > \(\frac{1}{3}\) of the pets are dogs > there are \(\frac{1}{3}*150=50\) dogs at the pet shop. Sufficient. (2) There are 20 more dogs than birds at the pet shop > \(d=b+20\) > \(\frac{1}{3}t=\frac{1}{5}t+20\), where \(t\) is the # of pets at the pet shop > \(t=150\) > \(\frac{1}{3}\) of the pets are dogs > there are \(\frac{1}{3}*150=50\) dogs at the pet shop. Sufficient. Answer: D.
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Re: Pets from the shop (mba.com)
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14 Nov 2010, 15:01
Statement 2 forms an equation
Suppose total pets are p
So p/3  p/5 = 20 Solving this, P=150, So Dogs are 50.
Answer: D



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At a certain pet shop, 1/3 of the pets are dogs and 1/5 of the p
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16 Feb 2013, 14:27
Does this assume that there are only dogs and birds in the pet shop? If so, shouldn't the problem state it?



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Re: a certain pet shop, 1/3 of pets are dogs, 1/5 of pets are
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17 Feb 2013, 09:19
Georgetowner wrote: Does this assume that there are only dogs and birds in the pet shop? If so, shouldn't the problem state it? If 1/3 of the pets are dogs, and 1/5 of the pets are birds, then only 1/3 + 1/5 = 8/15 of all pets are dogs or birds. So 7/15 of the pets need to be something other than dogs or birds. So no, the question is not assuming there are only dogs and birds in the shop.
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Re: At a certain pet shop, 1/3 of the pets are dogs and 1/5 of t
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18 Feb 2013, 04:35



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Re: At a certain pet shop, 1/3 of the pets are dogs and 1/5 of
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01 May 2013, 20:02
Hi Bunnel
Please clarify the quation
d=b+20..........or b=d+20................... I have gone with the 2nd one and made mistake.
Rgds Prasannajeet



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Re: At a certain pet shop, 1/3 of the pets are dogs and 1/5 of
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01 May 2013, 20:49
prasannajeet wrote: Hi Bunnel
Please clarify the quation
d=b+20..........or b=d+20................... I have gone with the 2nd one and made mistake.
Rgds Prasannajeet 20 more dogs than birds, no. of dogs are more...Hence, d=b+20 is correct
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Re: At a certain pet shop, 1/3 of the pets are dogs and 1/5 of
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02 May 2013, 01:08
Birds = 1/5th = 30, so total animals = 30 x 5 = 150 1/3rd are dogs, so 1/3 x 150 = 50 dogs
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Re: At a certain pet shop, 1/3 of the pets are dogs and 1/5 of
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02 May 2013, 03:12



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Re: At a certain pet shop, 1/3 of the pets are dogs and 1/5 of
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29 Jan 2017, 21:05
Question : Number of Dogs = ? Let the total number of pets be = P Given, (1/3)P = Dogs and (1/5)P = Birds We can find the number of dogs if we can find the value of P Statement 1) Number of birds = 30 => (1/5)P = 30 => P = 150, therefore Dog = 150/3 = 50 SUFFICIENT Statement 2) 20 more Dogs than Birds => Dogs = Birds + 20 => (1/3)P = (1/5)P + 20 i.e. (2/15)P = 20 i.e. P = 150 therefore Dog = = 150/3 = 50 SUFFICIENT Answer: Option D
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03 Feb 2017, 23:07
Please help with the following DS Q: At a certain pet shop, 1/3 of the pets are dogs and 1/5 are birds. How many of the pets are dogs? (1) There are 30 birds at the pet shop. (2) There are 20 more dogs than birds at the pet shop. I answered A, but the right answer seams to be D. Any one can help why statement 2 is also sufficient? Thanks in advance Sent from my SMN920C using GMAT Club Forum mobile app



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Re: At a certain pet shop, 1/3 of the pets are dogs and 1/5 of
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03 Feb 2017, 23:25



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Re: At a certain pet shop, 1/3 of the pets are dogs and 1/5 of
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03 Feb 2017, 23:32
Thanks guys U have been very helpful [THUMBS UP SIGN] Sent from my SMN920C using GMAT Club Forum mobile app



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Re: At a certain pet shop, 1/3 of the pets are dogs and 1/5 of
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19 Jan 2019, 05:54
ulm wrote: At a certain pet shop, 1/3 of the pets are dogs and 1/5 of the pets are birds. How many of the pets are dogs?
(1) There are 30 birds at the pet shop. (2) There are 20 more dogs than birds at the pet shop.
Target question: How many of the pets are dogs? Given: 1/3 of pets are dogs & 1/5 of pets are birds Let T = TOTAL number of pets. So, T/3 = number of dogsAnd T/5 = number of birds Statement 1: There are 30 birds at the pet shop So, T/5 = 30 This means that T = 150, which means T/3 = 50 (i.e., there are 50 dogs) Since we can answer the target question with certainty, statement 1 is SUFFICIENT Statement 2: There are 20 more dogs than birds at the pet shop. In other words, (# of birds) + 20 = # of dogs We can now write: T/5 + 20 = T/3 IMPORTANT: We could solve this equation for T, but we're not going to waste time doing so. We need only recognize that we could solve the equation for T, which means we can definitely find the value of T/3 (the number of dogs)Since we can answer the target question with certainty, statement 2 is SUFFICIENT Answer: D Cheers, Brent
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