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Total Number of Possibilities First Die: 6

Total Number of Possibilities Second Die: 6

Total Number of Possibilities Two Dice Together: 6 x 6 = 36

Dice have numbers 1 to 6.

Highest Possible Sum Using 1: 1 + 6 = 7

Highest Possible Sum Using 2: 2 + 6 = 8

Highest Possible Sum Using 3: 3 + 6 = 9

Highest Possible Sum Using 4: 4 + 6 = 10

If one of the dice shows 1 to 4, the sum will not be greater than 10.

Also, 5 + 5 = 10.

So, there are only three combinations that add up to sums greater than 10.

5 + 6 = 11

6 + 5 = 11

6 + 6 = 12

(Combinations That Add Up to Sums Greater Than 10)/(Total Combinations) = 3/36 = 1/12

The correct answer is (B).
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Total Outcomes = 6*6 =36
Fav Outcome= 6,4 6,5 6,6 only 3 cases which give sum greater than 10 so
Prob :3/3 =1/12
Answer B
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Bunuel
Two dice are rolled. What is the probability the sum will be greater than 10?

A. 1/9.
B. 1/12.
C. 5/36.
D. 1/6.
E. 1/5.

The rolls that will allow for a sum greater than 10 are:

(6,5) or (5,6) or (6,6)

Since there are a total of 6 x 6 = 36 outcomes, then the probability that the sum will be greater than 10 is 3/36 = 1/12.

Answer: B
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Why aren't we considering (6,6) twice?

Just the way (5,6) and (6,5) were considered as per "5 on the first dice and 6 on the 2nd dice and vice-versa", why shouldn't we consider 2 possibilities of (6,6) the same way?

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Why aren't we considering (6,6) twice?

Just the way (5,6) and (6,5) were considered as per "5 on the first dice and 6 on the 2nd dice and vice-versa", why shouldn't we consider 2 possibilities of (6,6) the same way?

Posted from my mobile device

Quoting an egmat quant experts response to this:

When two dice are rolled, we get a total of 36 outcomes. All the the possible outcomes are:

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

You can see in the above outcomes (5,6), (6,5), (6,6) are different possible outcomes of dices and occur only once. So when we are taking (6,5) & (5,6) we are essentially taking two different outcomes and not taking the outcomes twofold. Similarly (6,6) is a different outcome and if we take (6,6) outcome twofold it will be repetition of the outcome already taken.
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but if the dices are technically the "SAME" (eg. same color, size etc), (5,6) = (6,5), no?
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Given that Two dice are rolled and we need to find What is the probability the sum will be greater than 10?

As we are rolling two dice => Number of cases = \(6^2\) = 36

Out of the 36 cases only three cases are there where the sum will be higher than 10. These cases are (5,6), (6,5) and (6,6)

=> Probability that the sum will be greater than 10 = \(\frac{3}{36}\) = \(\frac{1}{12}\)

So, Answer will be B
Hope it helps!

Playlist on Solved Problems on Probability here

Watch the following video to MASTER Dice Rolling Probability Problems

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There are only 3 options out of 36 => 3/36=1/12
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