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Intern  Joined: 20 Jun 2011
Posts: 43

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15 00:00

Difficulty:   55% (hard)

Question Stats: 66% (02:45) correct 34% (03:01) wrong based on 242 sessions

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A. 6 hours and 40 minutes
B. 15 minutes
C. 12 minutes
D. 10 minutes
E. 3 minutes
Math Expert V
Joined: 02 Sep 2009
Posts: 59729

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4
2
superpus07 wrote:

A. 6 hours and 40 minutes
B. 15 minutes
C. 12 minutes
D. 10 minutes
E. 3 minutes

Say the time needed to download the movie from source A alone be $$a$$ minutes, from source B alone be $$b$$ minutes, and from source C alone be $$c$$ minutes. Next, since to download the movie from all three sources 2.5 hours (150 minutes) are needed then we have that:

$$\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=\frac{1}{150}$$ (we can sum the rates to get the combined rate of 3 sources).

Also, since to download the movie from A and C alone 4 hours (240 minutes) are needed then we have that:

$$\frac{1}{a}+\frac{1}{c}=\frac{1}{240}$$.

Subtract the second equation from the first one: $$\frac{1}{b}=\frac{1}{150}-\frac{1}{240}$$ --> $$\frac{1}{b}=\frac{1}{400}$$ --> $$b=400$$.

So, to download the movie from source B alone 400 minutes are needed, therefore to download the trailer, which is 40 time smaller than the movies 400/40=10 minutes are needed.

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Intern  Status: Facing the evil eyes of GMAT
Joined: 12 Apr 2012
Posts: 3
Location: Brazil
Concentration: General Management, Strategy
WE: Marketing (Consumer Products)

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5
1
Let's consider the movie's size is 100Mb

It takes 4 hours (240 min) to download the movie using only A and C.
It takes 2.5 hours (150 min) to download the movie using A, B and C.

So, we have:

(Va+Vb+Vc) = 100/150 = 2/3 Mb/min

Also:

(Va+Vc) = 100/240 = 5/12 Mb/min

Consequently:

(Va+Vc) + Vb = 2/3
Vb=2/3 - 5/12 = 1/4 Mb/min

The question states that the trailer is 40 times smaller than the movie. So, 100Mb / 40 = 2.5 Mb

Again:

Vb = Data / Time
1/4 = 2.5 / Time
Time = 2.5 / 0.25 = 10 minutes

Hope it helps!
##### General Discussion
Senior Manager  Joined: 13 Aug 2012
Posts: 397
Concentration: Marketing, Finance
GPA: 3.23

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1
$$\frac{1}{A}+\frac{1}{C}=\frac{1}{2.5}=\frac{2}{5}$$
$$\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=\frac{1}{4}$$

Combine the two equations to get $$\frac{1}{B}$$

$$-\frac{1}{B}=\frac{1}{4}-\frac{2}{5}=-\frac{3}{20}==>\frac{1}{B}=\frac{3}{20}$$

The time it takes to normally download is $$\frac{20}{3}hrs$$

Since the file is 40 times smaller, divide the time by 40.

$$t=\frac{20}{(3)(40)}=\frac{1}{6}hrs=10min$$
SVP  Joined: 06 Sep 2013
Posts: 1544
Concentration: Finance

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3
superpus07 wrote:

A. 6 hours and 40 minutes
B. 15 minutes
C. 12 minutes
D. 10 minutes
E. 3 minutes

1/A + 1/B + 1/C = 2/5
1/A + 1/C = 1/4

Then 1/B = 3/20

Now 40 times smaller then 20/3/40 = 20/120 = 1/6 hrs

10 minutes

So D is your friend today

Cheers!
J Manager  Joined: 26 Feb 2012
Posts: 88
Location: India
Concentration: General Management, Finance
WE: Engineering (Telecommunications)

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Hi Bunuel

I came down to 400 but wont answer. After ur explanation I am bit confused y u divide with 40...????

"So, to download the movie from source B alone 400 minutes are needed, therefore to download the trailer, which is 40 time smaller than the movies 400/40=10 minutes are needed".

Rgds
Prasannajeet
Math Expert V
Joined: 02 Sep 2009
Posts: 59729

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prasannajeet wrote:
Hi Bunuel

I came down to 400 but wont answer. After ur explanation I am bit confused y u divide with 40...????

"So, to download the movie from source B alone 400 minutes are needed, therefore to download the trailer, which is 40 time smaller than the movies 400/40=10 minutes are needed".

Rgds
Prasannajeet

It should be very easy:

To download the movie you need 400 minutes. The trailer is 40 times smaller than the movies. Hoe many minutes do you need to download the trailer?
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Manager  Joined: 20 Dec 2013
Posts: 222
Location: India

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Let the movie size be 400 u.
Given,A+C=4 hrs.
A+C=100 u/hr
And A+B+C=2.5 hrs or 400/2.5=160 u/hr
B alone=160-100=60 u/hr
Trailer=40 times smaller or400/40=10 u
B will take 10/60 hrs or 10 minutes.
Ans D

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Manager  Joined: 26 Feb 2012
Posts: 88
Location: India
Concentration: General Management, Finance
WE: Engineering (Telecommunications)

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Yes Bunuel ,It was a felony I made not being understand the simple equation...
Current Student B
Joined: 06 Sep 2016
Posts: 125
Location: Italy
Schools: EDHEC (A\$)
GMAT 1: 650 Q43 V37 GPA: 3.2
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Can someone please expalin why my reasoning is wrong?

R(a+c) = 1/4
1=1/4-Rb(5/2)
Rb=1/2

To calculate a file 40 times smaller:

1/40 = 1/2T

T=1/20x60 = 3 minutes
Senior SC Moderator V
Joined: 22 May 2016
Posts: 3747

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MvArrow wrote:
Can someone please expalin why my reasoning is wrong?

R(a+c) = 1/4
1=1/4-Rb(5/2)
Rb=1/2

To calculate a file 40 times smaller:

1/40 = 1/2T

T=1/20x60 = 3 minutes

MvArrow ,

1=1/4-Rb(5/2)

I'm not sure how you calculated Rb?

Rb should be 3/20.

R(a+b+c) = 2/5 (time is 5/2, invert for rate)
R(a+c) = 1/4

Rb: (2/5 - 1/4) = 3/20 = Rb

Then
$$\frac{\frac{1}{40}}{\frac{3}{20}}$$ = $$\frac{1}{6}$$ * 60 = 10 minutes

Also, I think this part isn't quite right either:

1/40 = 1/2T

Time would be 20/3: then 1/40 * 20/3 is 1/6 * 60 = 10 minutes

Hope that helps. If not, would you please explain how you got Rb? _________________
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