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Bill downloads the movie "Revenge of the Avengers" to his [#permalink]

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27 Jul 2012, 18:11

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45% (medium)

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69% (03:20) correct
31% (02:22) wrong based on 202 sessions

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Bill downloads the movie "Revenge of the Avengers" to his computer in 2.5 hours, using a download manager that downloads from 3 sources marked A, B and C. Each source provides download at a constant rate, but the rates of different sources are not necessarily identical. If the movie was downloaded from sources A and C alone, it would take 4 hours to complete the download. The next day, source B is available, but the other sources are inactive. How long will it take to download the trailer of the movie, a file that is 40 times smaller, from source B alone?

A. 6 hours and 40 minutes B. 15 minutes C. 12 minutes D. 10 minutes E. 3 minutes

Bill downloads the movie "Revenge of the Avengers" to his computer in 2.5 hours, using a download manager that downloads from 3 sources marked A, B and C. Each source provides download at a constant rate, but the rates of different sources are not necessarily identical. If the movie was downloaded from sources A and C alone, it would take 4 hours to complete the download. The next day, source B is available, but the other sources are inactive. How long will it take to download the trailer of the movie, a file that is 40 times smaller, from source B alone?

A. 6 hours and 40 minutes B. 15 minutes C. 12 minutes D. 10 minutes E. 3 minutes

Say the time needed to download the movie from source A alone be \(a\) minutes, from source B alone be \(b\) minutes, and from source C alone be \(c\) minutes. Next, since to download the movie from all three sources 2.5 hours (150 minutes) are needed then we have that:

\(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=\frac{1}{150}\) (we can sum the rates to get the combined rate of 3 sources).

Also, since to download the movie from A and C alone 4 hours (240 minutes) are needed then we have that:

\(\frac{1}{a}+\frac{1}{c}=\frac{1}{240}\).

Subtract the second equation from the first one: \(\frac{1}{b}=\frac{1}{150}-\frac{1}{240}\) --> \(\frac{1}{b}=\frac{1}{400}\) --> \(b=400\).

So, to download the movie from source B alone 400 minutes are needed, therefore to download the trailer, which is 40 time smaller than the movies 400/40=10 minutes are needed.

Re: Bill downloads the movie "Revenge of the Avengers" to his [#permalink]

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26 Dec 2013, 06:29

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This post received KUDOS

superpus07 wrote:

Bill downloads the movie "Revenge of the Avengers" to his computer in 2.5 hours, using a download manager that downloads from 3 sources marked A, B and C. Each source provides download at a constant rate, but the rates of different sources are not necessarily identical. If the movie was downloaded from sources A and C alone, it would take 4 hours to complete the download. The next day, source B is available, but the other sources are inactive. How long will it take to download the trailer of the movie, a file that is 40 times smaller, from source B alone?

A. 6 hours and 40 minutes B. 15 minutes C. 12 minutes D. 10 minutes E. 3 minutes

Solution Here, please follow

1/A + 1/B + 1/C = 2/5 1/A + 1/C = 1/4

Then 1/B = 3/20

Time taken to download in B is 20/3. Now 40 times smaller then 20/3/40 = 20/120 = 1/6 hrs

Re: Bill downloads the movie "Revenge of the Avengers" to his [#permalink]

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01 Feb 2014, 04:08

Hi Bunuel

I came down to 400 but wont answer. After ur explanation I am bit confused y u divide with 40...????

"So, to download the movie from source B alone 400 minutes are needed, therefore to download the trailer, which is 40 time smaller than the movies 400/40=10 minutes are needed".

I came down to 400 but wont answer. After ur explanation I am bit confused y u divide with 40...????

"So, to download the movie from source B alone 400 minutes are needed, therefore to download the trailer, which is 40 time smaller than the movies 400/40=10 minutes are needed".

Rgds Prasannajeet

It should be very easy:

To download the movie you need 400 minutes. The trailer is 40 times smaller than the movies. Hoe many minutes do you need to download the trailer?
_________________

Re: Bill downloads the movie "Revenge of the Avengers" to his [#permalink]

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01 Feb 2014, 20:19

Let the movie size be 400 u. Given,A+C=4 hrs. A+C=100 u/hr And A+B+C=2.5 hrs or 400/2.5=160 u/hr B alone=160-100=60 u/hr Trailer=40 times smaller or400/40=10 u B will take 10/60 hrs or 10 minutes. Ans D

Re: Bill downloads the movie "Revenge of the Avengers" to his [#permalink]

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08 Aug 2016, 11:24

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