stunn3r wrote:
If a, b, and c are 3-digit positive integers, where a=b+c, is the hundreds' digit of a equal to the hundreds' digit of b plus the hundreds' digit of c?
(1) The tens' digit of a is equal to the tens digit of b plus the tens' digit of c.
(2) The units' digit of a is equal to the units' digit of b plus the units' digit of c.
What is the source of this question?
The sum of the hundred's digits of a & b will equal the hundred's digit of c if nothing "carries" from the tens column.
123 + 351 = 474
123 + 358 = 481
Both of those lead to "yes" answer to the prompt question.
In order for statement #1 to be true, it must be true that nothing carries from the ones column to the tens column (only the first of the two example addition statements satisfies this) --- thus, statement #1 automatically implies statement #2. That's why statement #1, by itself, is sufficient --- it already completely contains the information in statement #2. That's why
(A) has to be the answer.
In other words, I am claiming that it is utterly impossible to find numbers that satisfy both the prompt condition and statement #1 but not statement #2. In order for
(C) to be the answer, there would have to be a case in which you could add two three digit numbers which met statement #1, did not meet statement #2, and the three-digit sum did not work out neatly in the hundreds column. You would have to able to find such a case, and I claim that finding such a case is impossible. That's why
(C) can't be the answer.
Does all this make sense?
Mike
hmm .. true .. Thanks mike
.. I figured it out when I retried the question but your explanation made it more clear.
I've this hard copy of 200 mixed bag questions .. these are good concept building and "makes you scratch your head a
" type questions. I am posting all which I think would give something to learn to forum members
I did first 40 of this set yesterday and posted around 7-8 questions. will post more, keep answering.