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# Box A and B each contain five cards numbered 1, 2, 3, 4 and 5. If one

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BSchool Forum Moderator
Joined: 29 Jan 2015
Posts: 1464
Location: India
WE: General Management (Non-Profit and Government)
Box A and B each contain five cards numbered 1, 2, 3, 4 and 5. If one  [#permalink]

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18 Nov 2019, 07:50
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Question Stats:

59% (01:29) correct 41% (02:05) wrong based on 44 sessions

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Box A and B each contain five cards numbered 1, 2, 3, 4 and 5. If one card is to be taken out from box A and B, what is the probability the product of the numbers in two cards will be less than 4?

(A) 2/25

(B) 4/25

(C) 1/5

(D) 1/4

(E) 2/5
Manager
Joined: 24 Sep 2019
Posts: 74
Box A and B each contain five cards numbered 1, 2, 3, 4 and 5. If one  [#permalink]

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18 Nov 2019, 12:13
1
To find the answer, find the number of combinations that will result in a product less than 4. in this case, opposites will count as separate draws, ie, 1*2 and 2*1 are 2 separate combinations.
1*1, 1*2, 1*3,2*1, and 3*1
there are 5 different combinations that qualify. to find probability, divide by the total number of combinations possible (5*5)=25
5/25=1/5
Ans=C
Intern
Joined: 19 Mar 2019
Posts: 6
Re: Box A and B each contain five cards numbered 1, 2, 3, 4 and 5. If one  [#permalink]

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20 Nov 2019, 08:52
Refer Attachment
Set A has 1 2 3 4 5
Set B has 1 2 3 4 5

So total 5x5=25 combinations

Now for product of any 2 to be less than 4
Set A becomes 1 2 3 4 5
Similarly Set B becomes 1 2 3 4 5

Combinations possible from the remaining
1x1 1x2 1x3 2x1 and 3x1

Other combinations does not meet the requirements

So the answer is 5/25 = 1/5
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IMG_20191120_211555.jpg [ 1015.5 KiB | Viewed 256 times ]

Target Test Prep Representative
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Re: Box A and B each contain five cards numbered 1, 2, 3, 4 and 5. If one  [#permalink]

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22 Nov 2019, 12:46
rohan2345 wrote:
Box A and B each contain five cards numbered 1, 2, 3, 4 and 5. If one card is to be taken out from box A and B, what is the probability the product of the numbers in two cards will be less than 4?

(A) 2/25

(B) 4/25

(C) 1/5

(D) 1/4

(E) 2/5

The options for products less than 4 are:

1,1

1,2 or 2,1

1,3 or 3,1

Since we have a total of 5 x 5 = 25 possible products the probability is 5/25 = 1/5.

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Re: Box A and B each contain five cards numbered 1, 2, 3, 4 and 5. If one   [#permalink] 22 Nov 2019, 12:46
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