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Bunuel
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The central angle is 360/7 so it has to be 540/7.

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Bunuel, can you post how you arrived at the solution?

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@chetan2u can you share the explanation?

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I need answer explanation.
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CrackVerbalGMAT can you help with solution here?
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Hi Bunuel, the answer which I'm getting is 540/7.


Please refer to the diagram below. A regular star polygon should be like this.


There are 7 equal arcs on the circle. arc AB = arc BC = arc CD = arc DE = arc EF = arc FG = arc GA


\(\angle{\alpha} = \frac{1}{2} * arc \space FEDC\)


Arc FEDC = arc FE + arc EB + arc BC = 3/7 th of the circle = 3/7 * 360 = 1080/7

Therefore \(\alpha = \frac{1}{2} * \frac{1080}{7} = \frac{540}{7}\)

Option E

Arun Kumar
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Heptagon.jpg
Heptagon.jpg [ 668.53 KiB | Viewed 7251 times ]

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Hi Bunuel, the answer which I'm getting is 540/7.


Please refer to the diagram below. A regular star polygon should be like this.


There are 7 equal arcs on the circle. arc AB = arc BC = arc CD = arc DE = arc EF = arc FG = arc GA


\(\angle{\alpha} = \frac{1}{2} * arc \space FEDC\)


Arc FEDC = arc FE + arc EB + arc BC = 3/7 th of the circle = 3/7 * 360 = 1080/7

Therefore \(\alpha = \frac{1}{2} * \frac{1080}{7} = \frac{540}{7}\)

Option E

Arun Kumar

How did u come to- angle a= 1/2 * arc fedc? Is there any formulae?

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Angle subtended by an arc/chord at the center is double of the angle subtended by the same arc/chord at the circumference.
Sorry can't post picture. You can google it.
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Hea234ven


How did u come to- angle a= 1/2 * arc fedc? Is there any formulae?

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There are a couple of equations based on the arc angle.

The simplest is that the arc angle is equal to the central angle subtended by the ends of the arc at the center.

Now this gets related to the property of the chord, where the the angle subtended by the chord at the center, is twice the angle subtended by the same chord at the circumference.

Based on this, the arc angle is twice the angle made by the ends of the arc at the circumference.


Hope this helps

Arun Kumar
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arc angles.jpg
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