Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 2208:30 AM PDT
-09:30 AM PDT
For many Indian MBA applicants, the default dream has long been a top US MBA. But as career goals, visa considerations, timelines, and global mobility priorities evolve, more candidates are seriously considering MBA programs in Europe.
May 2110:00 AM EDT
-11:59 PM EDT
Make the most of your break with the most realistic GMAT™ prep. Take up to $700 off select products.- Jun 10
06:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
27 Jan 2020, 01:57
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
88% (01:36) correct
12%
(01:54)
wrong
based on 234
sessions
History
Date
Time
Result
Not Attempted Yet
For any two numbers a and b, the operation a#b is given by the expression \(a^2 + 6ab + b^2\). If a#1 = -7, then a could be equal to
(A) -3
(B) -1
(C) -4
(D) 2
(E) 4
(A) -3
(B) -1
(C) -4
(D) 2
(E) 4
27 Jan 2020, 05:43
Kudos
Bookmarks
Replacing "b" with "1" in the definition of "a#b", we know we must get "-7" as a result, so:
a^2 + 6(a)(1) + 1^2 = -7
a^2 + 6a + 8 = 0
(a + 4)(a + 2) = 0
and a is either -4 or -2.
a^2 + 6(a)(1) + 1^2 = -7
a^2 + 6a + 8 = 0
(a + 4)(a + 2) = 0
and a is either -4 or -2.
30 Aug 2020, 10:34
Kudos
Bookmarks
Putting b = 1, we have a#1 = \(a^2 + 6a + 1 = -7\)
Since \(a^2\) is positive, therefore +6a has to be negative which means a has to be negative.
As per the options either a = -3, -1 or a = -4
Putting a = -3, we get [m]-3^2 + (6 * -3) + 1 = 9 - 18 + 1 = -8 which is not equal to -7
Putting a = -1, we get [m]-1^2 + (6 * -1) + 1 = 1 - 6 + 1 = -4 which is not equal to -7
Putting a = -4, we get [m]-4^2 + (6 * -4) + 1 = 16 - 24 + 1 = -7 which is equal to -7
Therefore a = -4
Option C
Arun Kumar
Since \(a^2\) is positive, therefore +6a has to be negative which means a has to be negative.
As per the options either a = -3, -1 or a = -4
Putting a = -3, we get [m]-3^2 + (6 * -3) + 1 = 9 - 18 + 1 = -8 which is not equal to -7
Putting a = -1, we get [m]-1^2 + (6 * -1) + 1 = 1 - 6 + 1 = -4 which is not equal to -7
Putting a = -4, we get [m]-4^2 + (6 * -4) + 1 = 16 - 24 + 1 = -7 which is equal to -7
Therefore a = -4
Option C
Arun Kumar
