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For each customer, a bakery charges p dollars for the first
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Updated on: 10 Feb 2015, 06:17
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81% (01:03) correct 19% (00:59) wrong based on 318 sessions
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For each customer, a bakery charges p dollars for the first loaf of bread bought by the customer and charges q dollars for each additional loaf bought by the customer. What is the value of p ? (1) A customer who buys 2 loaves is charged 10 percent less per loaf than a customer who buys a single loaf. (2) A customer who buys 6 loaves of bread is charged 10 dollars.
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Originally posted by dwag on 19 Sep 2006, 16:19.
Last edited by Ergenekon on 10 Feb 2015, 06:17, edited 2 times in total.
Edited the question and added the OA.




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Re: For each customer, a bakery charges p dollars for the first
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13 Aug 2013, 02:27
fozzzy wrote: What would be the equations for this question? For each customer, a bakery charges p dollars for the first loaf of bread bought by the customer and charges q dollars for each additional loaf bought by the customer. What is the value of p ?(1) A customer who buys 2 loaves is charged 10 percent less per loaf than a customer who buys a single loaf: Price of 2 loaves = $(p+q). Price per loaf = $(p+q)/2 Price of a single loaf = $p. Given that (p+q)/2=0.9p. Two unknowns. Not sufficient. (2) A customer who buys 6 loaves of bread is charged 10 dollars > p+5q=10. Not sufficient. (1)+(2) We have two distinct linear equations with two unknowns: (p+q)/2=0.9p and p+5q=10, thus we can solve for both p and q. Sufficient.. Answer: C. Hope it's clear.
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Re: For each customer, a bakery charges p dollars for the first
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19 Sep 2006, 17:34
Answer: C
Cost for first loaf = p
Cost for remaining = q
S1: Cost of two loaves = p+q
Price /loaf = (p+q)/2 = 0.9p (10% discount)
p+q = 1.8p
or q = 0.8p
or 4p 5q = 0
Not sufficient.
S2: 10 = p+5q
Not sufficient.
S1 & S2:
p+5q = 10
4p5q=0
or 5p = 10
p = 2
q = 4x2/5 = 1.6
Sufficient w/ 2 equations.



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Re: For each customer, a bakery charges p dollars for the first
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20 Sep 2006, 06:44
i cant get the warding of st one...........Help guys



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Re: For each customer, a bakery charges p dollars for the first
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20 Sep 2006, 06:58
Statement 1 says that when you buy 2 loaves of bread instead of 1, you get a discount of 10% per loaf.
If you buy 2, then the cost is (p+q) Cost per loaf = (p+q)/2 = 0.5p+0.5q
If you buy 1, the cost is p. Cost per loaf = p/1 = p
You get a 10% discount per loaf..
i.e. 0.5p+0.5q = 0.9p
or 0.5q = 0.4p
or 5q = 4p
yezz wrote: i cant get the warding of st one...........Help guys



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Re: For each customer, a bakery charges p dollars for the first
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20 Sep 2006, 08:58
Statement 1 says that when you buy 2 loaves of bread instead of 1, you get a discount of 10% per loaf.
If you buy 2, then the cost is (p+q) Cost per loaf = (p+q)/2 = 0.5p+0.5q
If you buy 1, the cost is p.
Cost per loaf = p/1 = p
You get a 10% discount per loaf..
i.e. 0.5p+0.5q = 0.9p
or 0.5q = 0.4p
or 5q = 4p
but dont you think that the part in read is the average cost per loaf not cost per loaf



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Re: For each customer, a bakery charges p dollars for the first
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20 Sep 2006, 09:04
For each customer, a bakery charges p dollars for the first loaf of bread bought by the customer and charges q dollars for each add'l loaf bought by the customer. What's the value of p?
(1) A customer who buys 2 loaves is charged 10% less per loaf than a customer who buys a single loaf.
(2) A customer who buys 6 loaves of bread is charged 10 dollars.
general formula to calculate price
x = p+nq where n is number of loafs in excess of one
from one
original price of two loafs is = p+q
fro one i think it means
p+q = 2(0.9)p = 1.8p
thus 0.8p=q
from two
p+5q = 10
both together
p+5(0.8p) = 10
thus 5p = 10 and p = 2 and q = 1.6
what is my mistake here



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Re: For each customer, a bakery charges p dollars for the first
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20 Sep 2006, 11:11
I used a combination of math and some guess work.
I have seen these type of problems before and made the mistake of thinking it was E in the past. However this time I knew it was D ...From the two stems it looks like you are going to get two equations with two variables which one can solve. I just made the sure the equations weren't equal to each other when I chose D...I didn't actually work all the way through the problem.



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Re: For each customer, a bakery charges p dollars for the first
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13 Aug 2013, 01:21
What would be the equations for this question?
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Re: For each customer, a bakery charges p dollars for the first
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26 Jan 2017, 06:51
Question stem tells you that p $ for 1st loaf and q $ for additional loaf. 1. if someone buys 2 loaf , he will be charged p+q $. price per laof = (p+q) / 2 $ if one buys only 1 loaf then one pays only p $ St1 tells that (p+q)/2 = (110%) p p/2+q/2 = 9/10p q=0.8 p Cant figure out p insufficient. 2. 6 loaves price is p+5q given as 10$ p+5q=10 Insufficient. Together 1 & 2 p+5*0.8p = 10 p =2$
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Re: For each customer, a bakery charges p dollars for the first
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08 Oct 2017, 09:41
Hi In this why cant the answer be B. We have the equation, p+5q=10 The only possible value that q can take is 1. Thus, we can get p as 5. Bunuel wrote: fozzzy wrote: What would be the equations for this question? For each customer, a bakery charges p dollars for the first loaf of bread bought by the customer and charges q dollars for each additional loaf bought by the customer. What is the value of p ?(1) A customer who buys 2 loaves is charged 10 percent less per loaf than a customer who buys a single loaf: Price of 2 loaves = $(p+q). Price per loaf = $(p+q)/2 Price of a single loaf = $p. Given that (p+q)/2=0.9p. Two unknowns. Not sufficient. (2) A customer who buys 6 loaves of bread is charged 10 dollars > p+5q=10. Not sufficient. (1)+(2) We have two distinct linear equations with two unknowns: (p+q)/2=0.9p and p+5q=10, thus we can solve for both p and q. Sufficient.. Answer: C. Hope it's clear.



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Re: For each customer, a bakery charges p dollars for the first
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08 Oct 2017, 13:55
sinhap07 wrote: Hi
In this why cant the answer be B.
We have the equation, p+5q=10
The only possible value that q can take is 1. Thus, we can get p as 5.
You don't necessarily know that q is an integer. Dollar amounts can be nonintegers. For instance, the first loaf could cost 3.2 dollars, and the remaining 5 loaves could cost 1.36 dollars each. 3.2 + 5(1.36) = 10, which fits statement 2.
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Re: For each customer, a bakery charges p dollars for the first &nbs
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