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Updated on: 28 Mar 2018, 20:50
Originally posted by rishabhmishra on 16 Mar 2018, 00:29.
Last edited by Bunuel on 28 Mar 2018, 20:50, edited 1 time in total.
Last edited by Bunuel on 28 Mar 2018, 20:50, edited 1 time in total.
Edited the question.
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
51% (01:29) correct
49%
(01:24)
wrong
based on 544
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For how many integers, denoted by "q", is \(2^{|q|} =q^2\)?
A. ONE
B. TWO
C. THREE
D. FOUR
E. MORE THAN FOUR.
A. ONE
B. TWO
C. THREE
D. FOUR
E. MORE THAN FOUR.
16 Mar 2018, 00:37
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rishabhmishra
This is possible for 4 integers 2, 4, -2 and -4
as \(2^4\) = 16
\(4^2\)=16
\(2^2\)= 4
and for - from the equation above those negative will converted into + by squaring or by [q]
28 Mar 2018, 12:20
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Hi, I have a discrepancy with the answer and approach to the solution, it is not mentioned that [q] is absolute value of q, generally |q| is taken to be so. Also, in many cases the square brackets are used for greatest or smallest integer above or below a value type of questions, or it could simply mean square brackets. So i believe it is necessary for the symbol to be expressed correctly. Please correct me if I am wrong. 
