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20 Mar 2019, 20:11
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prat29
We know the mass of the non-water part is the same in the initial and final product, so we can equate them
let the weights of dates be, \(W_i\) and \(W_f\)
and concentrations of non-water part be \(C_i\) and \(C_f\)
since the mass is same,
\(W_i\) * \(C_i\) = \(W_f\)*\(C_f\)
\(W_i\) * 10 = \(W_f\) * 72
\(\frac{W_i}{W_f} = \frac{36}{5}\)
Thus, \(W_f\) = 5 kg
Archit3110
Major Poster
05 Aug 2019, 11:07
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prat29
fresh dates = 90% water and 10% weight
dry dates; 28% water and 72% weight
so 36 kgs of fresh dates has 3.6 kg weigh
.72*x=3.6
5kgs
IMO A
20 Jun 2025, 04:01
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can teeter totter method be used here?
