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Given the circle to the right, with center O, diameter AOB, a radius

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Math Expert
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Given the circle to the right, with center O, diameter AOB, a radius  [#permalink]

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New post 23 Mar 2016, 12:47
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

92% (00:41) correct 8% (01:21) wrong based on 63 sessions

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Marshall & McDonough Moderator
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Re: Given the circle to the right, with center O, diameter AOB, a radius  [#permalink]

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New post 23 Mar 2016, 20:38
ACB is a right angle triangle.
AB = 10 is the hypotenuse
BC = 8
AC = \(\sqrt{10^2 - 8^2}\) = 6

Answer: C
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Re: Given the circle to the right, with center O, diameter AOB, a radius  [#permalink]

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New post 04 Apr 2016, 15:16
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Re: Given the circle to the right, with center O, diameter AOB, a radius  [#permalink]

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New post 01 Dec 2019, 15:51
Hi All,

We're told that in the circle with center O, AOB is the diameter, the radius of the circle is 5 and triangle ABC is inscribed. We're asked for the the length of AC. This question is based on some specific Geometry patterns - and if you recognize them, then you can answer this question without doing much math at all.

To start, any triangle in a circle that has all 3 vertices ON the circumference AND has one side that is the diameter of the circle is a RIGHT TRIANGLE. Thus, Angle C is a 90-degree angle.

Next, since the radius of the circle is 5, the diameter is 10. We now know two of the sides of the right triangle (8 and 10 - which is the hypotenuse). You can use the Pythagorean Theorem (A^2 + B^2 = C^2) to find the missing side OR you might recognize that we're dealing with a 3/4/5 right triangle that has been 'doubled' (into a 6/8/10 right triangle). Thus, the missing side is 6.

Final Answer:

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Re: Given the circle to the right, with center O, diameter AOB, a radius   [#permalink] 01 Dec 2019, 15:51
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