It is currently 18 Oct 2017, 17:44

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

GMAT Prep: Geometry

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Manager
Manager
avatar
Joined: 23 Jun 2008
Posts: 140

Kudos [?]: 144 [0], given: 0

GMAT Prep: Geometry [#permalink]

Show Tags

New post 23 Jul 2008, 18:16
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Question in attachment.
Attachments

GMAT Prep- Geometry_part2.doc [59.5 KiB]
Downloaded 439 times

To download please login or register as a user

Kudos [?]: 144 [0], given: 0

Intern
Intern
avatar
Joined: 22 Apr 2008
Posts: 36

Kudos [?]: 70 [0], given: 0

Re: GMAT Prep: Geometry [#permalink]

Show Tags

New post 24 Jul 2008, 02:48
OP = 2
because of circle radius, OP = OQ

therefore s^2+t^2 = 4 --- 1

now using Pyth Thm

OP^2+OQ^2 = PQ^2

s^2+t^2+4=(s+sq.root(3))^2 + (t-1)^2

solving this we get t^2 = 3s^2

hence using (1) we get s= 1


what is OA?
thanks

Kudos [?]: 70 [0], given: 0

Senior Manager
Senior Manager
User avatar
Joined: 14 Mar 2007
Posts: 295

Kudos [?]: 39 [0], given: 3

Location: Hungary
Re: GMAT Prep: Geometry [#permalink]

Show Tags

New post 24 Jul 2008, 04:17
I also got 1 as the result.

Kudos [?]: 39 [0], given: 3

Manager
Manager
avatar
Joined: 23 Jun 2008
Posts: 140

Kudos [?]: 144 [0], given: 0

Re: GMAT Prep: Geometry [#permalink]

Show Tags

New post 24 Jul 2008, 07:01
OA is 1. Thanks for the solution!

Kudos [?]: 144 [0], given: 0

SVP
SVP
avatar
Joined: 17 Jun 2008
Posts: 1534

Kudos [?]: 279 [0], given: 0

Re: GMAT Prep: Geometry [#permalink]

Show Tags

New post 24 Jul 2008, 07:20
And what is the explanation for OA?

Kudos [?]: 279 [0], given: 0

Senior Manager
Senior Manager
User avatar
Joined: 19 Mar 2008
Posts: 351

Kudos [?]: 68 [0], given: 0

Re: GMAT Prep: Geometry [#permalink]

Show Tags

New post 24 Jul 2008, 07:37
Draw a line from P to Q

Let the intercept of line segment PQ and y axis be A

PO^2 = 1^2 + (-3^0.5)^2
PO = 2
so, QO = 2

consider triangle POA:
COS angle POA = AO/PO = 1/2
so, angle POA = 60

So angle QOA = 30
s/QO = SIN angle QOA = SIN 30 = 1/2
As QO = 2
s = 1

Kudos [?]: 68 [0], given: 0

Intern
Intern
avatar
Joined: 19 Feb 2007
Posts: 9

Kudos [?]: 3 [0], given: 0

Re: GMAT Prep: Geometry [#permalink]

Show Tags

New post 26 Jul 2008, 03:05
Not to be a spoiler, but I think the use of COS, SIN creates more complications especially for those of us that has forgotten these rules. :oops:

I think this question really comes down to knowledge and usage of the Pyth Thm. Once you can find out OP, OA (created by test taker), PQ (PA, AQ) and OQ. Then we are quickly are able to find the coordinates of s and t. And therefore establish that s is 1.

Correct me if I am wrong.

Kudos [?]: 3 [0], given: 0

Intern
Intern
avatar
Joined: 05 Aug 2008
Posts: 20

Kudos [?]: 2 [0], given: 0

Re: GMAT Prep: Geometry [#permalink]

Show Tags

New post 08 Aug 2008, 10:45
Is the angle between PO and OQ 90 degrees? If so, can't we just do the following:

PO = sqrt(sqrt(3)^2+1^2) = 2 = QO since both PO and OQ represent the radii of the circle
since PO = QO and the angle between them is 90 degrees, then the other 2 angles in the POQ triangle are 45 degrees and thus PQ = 2*sqrt(2)

since we know that PQ comprises of the x-portion of PO and the x-portion of OQ and we know the x-portion of PO = sqrt(3) than the x-portion of OQ is 2*sqrt(2)-sqrt(3) which is approximately 1.09 (not exactly 1, but close).

Kudos [?]: 2 [0], given: 0

SVP
SVP
User avatar
Joined: 07 Nov 2007
Posts: 1792

Kudos [?]: 1059 [0], given: 5

Location: New York
Re: GMAT Prep: Geometry [#permalink]

Show Tags

New post 08 Aug 2008, 11:12
balboa wrote:
Question in attachment.


Here is my approach.

OP ^2= (-sqrt(3))^2 + 1^2
-- OP =2 and OQ=2

SLOPE OF OP = Y2-Y1/X2-X1 = (1-0)/(-SQRT(3) -1) = -1/SQRT(3)
SLOPE OF OQ = SQRT(3)
becaue OP and OQ are perpendicular.

t-0/s-0 = sqrt(3) ---> t=s *sqrt(3)
s*s + t*t = 2*2
s*s (3+1)=4 --> s=1
_________________

Your attitude determines your altitude
Smiling wins more friends than frowning

Kudos [?]: 1059 [0], given: 5

VP
VP
avatar
Joined: 17 Jun 2008
Posts: 1374

Kudos [?]: 406 [0], given: 0

Re: GMAT Prep: Geometry [#permalink]

Show Tags

New post 08 Aug 2008, 11:21
from the figure we get radius=2
also s^2+t^2=4 ------->I
(s+3^1/2)^2 +(t-1)^2=8 => s*(3 ^ 1/2)=t => s=1 or s=-1 =>
s=1 is the correct solution 1t coordinate

hence IMO B
_________________

cheers
Its Now Or Never

Kudos [?]: 406 [0], given: 0

SVP
SVP
User avatar
Joined: 07 Nov 2007
Posts: 1792

Kudos [?]: 1059 [0], given: 5

Location: New York
Re: GMAT Prep: Geometry [#permalink]

Show Tags

New post 09 Aug 2008, 06:24
balboa wrote:
Question in attachment.



Just my 2 cents without using pen and paper.

Right angle triagle two sides -sqrt(3), 1 So other side OP =2
OQ=OP =2
OP and OQ are perpendicular lines
point (Q-(x,y)) should be inthe ratio 1:sqrt(3)
obvisously other side is 2
clearly x=1 y=sqrt(3)
_________________

Your attitude determines your altitude
Smiling wins more friends than frowning

Kudos [?]: 1059 [0], given: 5

Re: GMAT Prep: Geometry   [#permalink] 09 Aug 2008, 06:24
Display posts from previous: Sort by

GMAT Prep: Geometry

  post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.