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Harriet wants to put up fencing around three sides of her

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fiendex
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Harriet wants to put up fencing around three sides of her [#permalink] New post   05 Feb 2012, 15:55
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Harriet wants to put up fencing around three sides of her rectangular yard and leave a side of 20 feet unfenced. If the yard has an area of 680 square feet, how many feet of fencing does she need?

A) 34
B) 40
C) 68
D) 88
E) 102
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D
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Bunuel
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Re: Harriet wants to put up fencing around three sides of her [#permalink] New post   05 Feb 2012, 16:01
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fiendex wrote:
Harriet wants to put up fencing around three sides of her rectangular yard and leave a side of 20 feet unfenced. If the yard has an area of 680 square feet, how many feet of fencing does she need?

A) 34
B) 40
C) 68
D) 88
E) 102


As the one side of her rectangular yard is 20 feet and the area is 680 square feet, then x*20=680 (where x is the other side of a rectangular yard) --> x=34 feet;

She wants to put up fencing around three sides, but one with 20 feet, hence she'll need 2*34+20=88 feet of fencing.

Answer: D.

Hope it's clear.
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BrentGMATPrepNow
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Re: Harriet wants to put up fencing around three sides of her [#permalink] New post   08 Oct 2019, 09:09
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fiendex wrote:
Harriet wants to put up fencing around three sides of her rectangular yard and leave a side of 20 feet unfenced. If the yard has an area of 680 square feet, how many feet of fencing does she need?

A) 34
B) 40
C) 68
D) 88
E) 102


Here's a sketch of what we're dealing with:


Given: area of the rectangle = 680

Area = (base)(height) = (x)(20) = 20x

So: 20x = 680
Solve: x = 680/20 = 34

We now have:


Perimeter = 34 + 34 + 20 = 88

Answer: D

Cheers,
Brent
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Re: Harriet wants to put up fencing around three sides of her [#permalink] New post   26 Apr 2016, 14:22
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Area of the yard = 680 sq.feet
one side of the rectangle given as 20 feet
other side = 680/20 = 34 feet
required fencing = 2 * 34 + 20 = 88 feet of fencing
Answer - D
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Bunuel
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Harriet wants to put up fencing around three sides of her [#permalink] New post   05 Oct 2017, 01:43
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23. Geometry




24. Coordinate Geometry




25. Triangles




26. Polygons




27. Circles




28. Rectangular Solids and Cylinders




29. Graphs and Illustrations


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Re: Harriet wants to put up fencing around three sides of her rectangular [#permalink] New post   05 Oct 2017, 02:21
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Area of rectangular yard = 680
one of the side = 20
so we get, length * breadth = 680, i.e. l*20=680, and hence l=34
as one side of length 20 feet is to be left unfenced, so total length to be fenced = 34+34+20 = 88 feet
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Re: Harriet wants to put up fencing around three sides of her rectangular [#permalink] New post   09 Oct 2017, 16:52
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Bunuel wrote:
Harriet wants to put up fencing around three sides of her rectangular yard and leave a side of 20 feet unfenced. If the yard has an area of 680 square feet, how many feet of fencing does she need?

(A) 34
(B) 40
(C) 68
(D) 88
(E) 102


Since the yard is a rectangle and one side is 20, which we can call the length, then the width (w) is:

680 = 20w

34 = w

Thus, she needs 34 + 34 + 20 = 88 feet of fencing.

Answer: D
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Re: Harriet wants to put up fencing around three sides of her rectangular [#permalink] New post   05 Oct 2017, 01:52
Area of the yard = 680 sq.feet
one side of the rectangle given as 20 feet
other side = 680/20 = 34 feet
required fencing = 2 * 34 + 20 = 88 feet of fencing
Answer - D
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CEdward
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Re: Harriet wants to put up fencing around three sides of her [#permalink] New post   11 Feb 2021, 22:13
20x = 680 ---> x = 34

P = (34 x 2) + 20 = 88

Answer is D.
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Re: Harriet wants to put up fencing around three sides of her [#permalink] New post   10 Apr 2024, 23:15
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