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Sub 505 Level|   Geometry|            
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Area of the yard = 680 sq.feet
one side of the rectangle given as 20 feet
other side = 680/20 = 34 feet
required fencing = 2 * 34 + 20 = 88 feet of fencing
Answer - D
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23. Geometry




24. Coordinate Geometry




25. Triangles




26. Polygons




27. Circles




28. Rectangular Solids and Cylinders




29. Graphs and Illustrations


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Area of the yard = 680 sq.feet
one side of the rectangle given as 20 feet
other side = 680/20 = 34 feet
required fencing = 2 * 34 + 20 = 88 feet of fencing
Answer - D
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Area of rectangular yard = 680
one of the side = 20
so we get, length * breadth = 680, i.e. l*20=680, and hence l=34
as one side of length 20 feet is to be left unfenced, so total length to be fenced = 34+34+20 = 88 feet
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Bunuel
Harriet wants to put up fencing around three sides of her rectangular yard and leave a side of 20 feet unfenced. If the yard has an area of 680 square feet, how many feet of fencing does she need?

(A) 34
(B) 40
(C) 68
(D) 88
(E) 102

Since the yard is a rectangle and one side is 20, which we can call the length, then the width (w) is:

680 = 20w

34 = w

Thus, she needs 34 + 34 + 20 = 88 feet of fencing.

Answer: D
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20x = 680 ---> x = 34

P = (34 x 2) + 20 = 88

Answer is D.
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