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How many bits of computer memory will be required to store the integer
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03 Jul 2017, 13:41
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How many bits of computer memory will be required to store the integer x, where x =  \(\sqrt{810,000}\) if each digit requires 4 bits of memory and the sign of x requires 1 bit? (A) 25 (B) 24 (C) 17 (D) 13 (E) 12
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Re: How many bits of computer memory will be required to store the integer
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03 Jul 2017, 13:51
carcass wrote: How many bits of computer memory will be required to store the integer x, where x =  \(\sqrt{810,000}\) if each digit requires 4 bits of memory and the sign of x requires 1 bit?
(A) 25 (B) 24 (C) 17 (D) 13 (E) 12 Hi  carcass  Could you please check the validity of the question? I think either the question is incorrect or the answer options are not matching. Your question only contains x =  \(\sqrt{810,000}\)
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Re: How many bits of computer memory will be required to store the integer
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03 Jul 2017, 13:55
The question is correct. I checked it out
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Re: How many bits of computer memory will be required to store the integer
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03 Jul 2017, 14:05
carcass wrote: The question is correct. I checked it out Hello carcass, may be I am wrong. however, however for me this problem looks exactly similar to the problem in GMAT PLUS where the question is: \({}\sqrt{810,000}  \sqrt{810,000}\) Followed by this option (A) 25 (B) 24 (C) 17 (D) 13 (E) 12 Answer for the above question is D  13 and solution is as per below: \(900  900 = 1800\) As there are three unique digits and each units require 4 bits answer will be \(= 4*3 + 1 = 12+1 = 13\) ====== Coming back to your question, where you have only given \({}\sqrt{810,000}\) Which will be \(900\) And answer would be \(= 4*2 + 1 = 8+1 = 9\) Please confirm if I am wrong.
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Re: How many bits of computer memory will be required to store the integer
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03 Jul 2017, 20:31
carcass wrote: How many bits of computer memory will be required to store the integer x, where x =  \(\sqrt{810,000}\) if each digit requires 4 bits of memory and the sign of x requires 1 bit?
(A) 25 (B) 24 (C) 17 (D) 13 (E) 12 x =  \(\sqrt{810,000}\) =  900 Each digit requires 4 bits of memory and sign of x requires 1 bit Total number of bits of computer memory required = 4*3 + 1 = 13 Answer D
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Re: How many bits of computer memory will be required to store the integer
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03 Jul 2017, 21:06
ydmuley wrote: carcass wrote: The question is correct. I checked it out Hello carcass, may be I am wrong. however, however for me this problem looks exactly similar to the problem in GMAT PLUS where the question is: \({}\sqrt{810,000}  \sqrt{810,000}\) Followed by this option (A) 25 (B) 24 (C) 17 (D) 13 (E) 12 Answer for the above question is D  13 and solution is as per below: \(900  900 = 1800\) As there are three unique digits and each units require 4 bits answer will be \(= 4*3 + 1 = 12+1 = 13\) ====== Coming back to your question, where you have only given \({}\sqrt{810,000}\) Which will be \(900\) And answer would be \(= 4*2 + 1 = 8+1 = 9\) Please confirm if I am wrong. 900 has 3 digits. Note that you are not looking for just the unique digits. You need 4 bits to store each of the digit to know the number. Else, if you just store 9 and 0, the number could be 90, 990, 900 ... etc
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Re: How many bits of computer memory will be required to store the integer
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13 Mar 2018, 20:42
ydmuley wrote: carcass wrote: The question is correct. I checked it out Hello carcass, may be I am wrong. however, however for me this problem looks exactly similar to the problem in GMAT PLUS where the question is: \({}\sqrt{810,000}  \sqrt{810,000}\) Followed by this option (A) 25 (B) 24 (C) 17 (D) 13 (E) 12 Answer for the above question is D  13 and solution is as per below: \(900  900 = 1800\) As there are three unique digits and each units require 4 bits answer will be \(= 4*3 + 1 = 12+1 = 13\) ====== Coming back to your question, where you have only given \({}\sqrt{810,000}\) Which will be \(900\) And answer would be \(= 4*2 + 1 = 8+1 = 9\) Please confirm if I am wrong. 3 unique digits means: 1) 4 bits of memory 2) sign x requires 3) x requires 1 bit Are these the 3 unique digits for which we did 4*3? Sent from my MI 5 using GMAT Club Forum mobile app



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Re: How many bits of computer memory will be required to store the integer
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13 Mar 2018, 21:39
VeritasPrepKarishma wrote: ydmuley wrote: carcass wrote: The question is correct. I checked it out Hello carcass, may be I am wrong. however, however for me this problem looks exactly similar to the problem in GMAT PLUS where the question is: \({}\sqrt{810,000}  \sqrt{810,000}\) Followed by this option (A) 25 (B) 24 (C) 17 (D) 13 (E) 12 Answer for the above question is D  13 and solution is as per below: \(900  900 = 1800\) As there are three unique digits and each units require 4 bits answer will be \(= 4*3 + 1 = 12+1 = 13\) ====== Coming back to your question, where you have only given \({}\sqrt{810,000}\) Which will be \(900\) And answer would be \(= 4*2 + 1 = 8+1 = 9\) Please confirm if I am wrong. 900 has 3 digits. Note that you are not looking for just the unique digits. You need 4 bits to store each of the digit to know the number. Else, if you just store 9 and 0, the number could be 90, 990, 900 ... etc Hi, Just wanted to understand why we are not considering that the root of 81,000 shall have two values one positive and the other negative. Would appreciate it if anyone could give clarity on this
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Re: How many bits of computer memory will be required to store the integer
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13 Mar 2018, 21:44
boomtangboy wrote: Hi, Just wanted to understand why we are not considering that the root of 81,000 shall have two values one positive and the other negative. Would appreciate it if anyone could give clarity on this \(\sqrt{...}\) is the square root sign, a function (called the principal square root function), which cannot give negative result. So, this sign (\(\sqrt{...}\)) always means nonnegative square root. The graph of the function f(x) = √xNotice that it's defined for nonnegative numbers and is producing nonnegative results. TO SUMMARIZE: When the GMAT provides the square root sign for an even root, such as a square root, fourth root, etc. then the only accepted answer is the nonnegative root. That is: \(\sqrt{9} = 3\), NOT +3 or 3; \(\sqrt[4]{16} = 2\), NOT +2 or 2; Notice that in contrast, the equation \(x^2 = 9\) has TWO solutions, +3 and 3. Because \(x^2 = 9\) means that \(x =\sqrt{9}=3\) or \(x=\sqrt{9}=3\).
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Re: How many bits of computer memory will be required to store the integer
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13 Mar 2018, 22:18
Bunuel Quote: Notice that in contrast, the equation \(x^2 = 9\) has TWO solutions, +3 and 3. Because \(x^2 = 9\) means that \(x =\sqrt{9}=3\) or \(x=\sqrt{9}=3\) Is highlighted text same as taking absolute modulus? \(x^2 = 9\) Taking square root on both sides, we get x = 9 or x = 3 or x = 3.
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Re: How many bits of computer memory will be required to store the integer
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13 Mar 2018, 22:29
adkikani wrote: Bunuel Quote: Notice that in contrast, the equation \(x^2 = 9\) has TWO solutions, +3 and 3. Because \(x^2 = 9\) means that \(x =\sqrt{9}=3\) or \(x=\sqrt{9}=3\) Is highlighted text same as taking absolute modulus? \(x^2 = 9\) Taking square root on both sides, we get x = 9 or x = 3 or x = 3. Absolutely. Since \(\sqrt{x^2}=x\), then \(x^2 = 9\) is equivalent to x = 3, which gives x = 3 or x = 3.
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Re: How many bits of computer memory will be required to store the integer
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