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06 Jun 2019, 00:01
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D
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Difficulty:
15%
(low)
Question Stats:
74% (00:57) correct
26%
(01:11)
wrong
based on 173
sessions
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How many different positive integers are factors of 225 ?
(A) 4
(B) 6
(C) 7
(D) 9
(E) 11
(A) 4
(B) 6
(C) 7
(D) 9
(E) 11
06 Jun 2019, 00:08
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Bunuel
How many different positive integers are factors of 225 ?
(A) 4
(B) 6
(C) 7
(D) 9
(E) 11
(A) 4
(B) 6
(C) 7
(D) 9
(E) 11
225 = 15^2 = 3^2*5^2
Number of positive integer factors = (2 + 1)*(2 + 1) = 9
Option D
Posted from my mobile device
Updated on: 17 May 2021, 07:37
Originally posted by BrentGMATPrepNow on 06 Jun 2019, 06:39.
Last edited by BrentGMATPrepNow on 17 May 2021, 07:37, edited 1 time in total.
Last edited by BrentGMATPrepNow on 17 May 2021, 07:37, edited 1 time in total.
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Bunuel
How many different positive integers are factors of 225 ?
(A) 4
(B) 6
(C) 7
(D) 9
(E) 11
-------ASIDE--------------(A) 4
(B) 6
(C) 7
(D) 9
(E) 11
If N = (p^a)(q^b)(r^c)..., where p, q, r,...(etc.) are prime numbers, then the total number of positive divisors of N is equal to (a+1)(b+1)(c+1)...
Example: 14000 = (2^4)(5^3)(7^1)
So, the number of positive divisors of 14000 = (4+1)(3+1)(1+1) = (5)(4)(2) = 40
-------------------------
225= (3^2)(5^2)
So, the number of positive divisors of 225 = (2+1)(2+1) = (3)(3) = 9
Answer: D
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