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How many digits will be there to the right of the decimal

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How many digits will be there to the right of the decimal  [#permalink]

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New post 13 Apr 2013, 00:44
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  65% (hard)

Question Stats:

53% (01:01) correct 47% (00:55) wrong based on 169 sessions

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How many digits will be there to the right of the decimal point in the product of 95.75 and .02554 ?

A. 5
B. 6
C. 7
D. 8
E. None of these

I thought it was easy. I don't really need to multiply the numbers, but i was wrong. Please share your thoughts on this question.

Thanks & Regards
Vinni
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Re: How many digits will be there to the right of the decimal  [#permalink]

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New post 13 Apr 2013, 02:22
5
Thanks for your explanation :-D

Regards
Vinni

rakeshd347 wrote:


Hi Vinni

It is very easy just a small trick that GMAT test you on your ability to think…..there are 6 digits if you multiply them both just by counting the digits on the right hand side of decimal of each number than it comes out to be 7 and you would have choose 7 right….but here is the trick if you see such an easy question in GMAT as yourself again there must be some catch in it and the catch here is that one of the number involves 5 in the end (95.75) and other number involves even number in the end which is 4(.02554). So when you multiply 5 and 4 there will be a zero in the end and there is no point showing the zero in the end of a decimal.

If you didn't understand let me choose a simple example.
Multiple 0.5 with 0.7 how many digits will be there in the multiplication after the decimal….obviously 2 because one number involves 5 but other doesn't involve even number.
Multiply 0.5 with 0.2 how many digits will be there in the multiplication after the decimal….now you will say 2 again its wrong because 0.1 and 0.10 is same so there is only 1 digit. So the right answer would be 1.

So whenever you have a 5 involved in the end of a number and even number at the end of the other number then number of digits will be less by 1 from original.

Please KUDOS me if this helps explain better.
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Re: How many digits will be there to the right of the decimal  [#permalink]

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New post 15 Jul 2014, 20:23
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vinnik wrote:
Thanks for your explanation :-D

Regards
Vinni

rakeshd347 wrote:


Hi Vinni

It is very easy just a small trick that GMAT test you on your ability to think…..there are 6 digits if you multiply them both just by counting the digits on the right hand side of decimal of each number than it comes out to be 7 and you would have choose 7 right….but here is the trick if you see such an easy question in GMAT as yourself again there must be some catch in it and the catch here is that one of the number involves 5 in the end (95.75) and other number involves even number in the end which is 4(.02554). So when you multiply 5 and 4 there will be a zero in the end and there is no point showing the zero in the end of a decimal.

If you didn't understand let me choose a simple example.
Multiple 0.5 with 0.7 how many digits will be there in the multiplication after the decimal….obviously 2 because one number involves 5 but other doesn't involve even number.
Multiply 0.5 with 0.2 how many digits will be there in the multiplication after the decimal….now you will say 2 again its wrong because 0.1 and 0.10 is same so there is only 1 digit. So the right answer would be 1.

So whenever you have a 5 involved in the end of a number and even number at the end of the other number then number of digits will be less by 1 from original.

Please KUDOS me if this helps explain better.


I would like to add there that if the last two digits are divisible by 4, then the number of digits would be less by 2 from the original.

Had it been product of
95.75 and .02564 = 24.5503

OR

95.75 and .02544 = 24.3588

Same test applies on both the numbers. 75 is a multiple of 25 & 64 is multiple of 4; so resultant product will always give 100 (2 zero's at the end)

We require to focus on last 2 digits of both numbers to have a airtight answer :)
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Re: How many digits will be there to the right of the decimal  [#permalink]

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New post 09 Dec 2015, 19:19
did it the long way. The trick here is that the last digit is 0, and thus is not counted. In general, the number of digits should be the sum of digits after the decimal point. But in this case, we get 2.4454550. since 0 doesn't count, we thus have only 6 digits.c
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Re: How many digits will be there to the right of the decimal  [#permalink]

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New post 20 Dec 2015, 09:47
PareshGmat wrote:
vinnik wrote:
Thanks for your explanation :-D

Regards
Vinni

rakeshd347 wrote:


Hi Vinni

It is very easy just a small trick that GMAT test you on your ability to think…..there are 6 digits if you multiply them both just by counting the digits on the right hand side of decimal of each number than it comes out to be 7 and you would have choose 7 right….but here is the trick if you see such an easy question in GMAT as yourself again there must be some catch in it and the catch here is that one of the number involves 5 in the end (95.75) and other number involves even number in the end which is 4(.02554). So when you multiply 5 and 4 there will be a zero in the end and there is no point showing the zero in the end of a decimal.

If you didn't understand let me choose a simple example.
Multiple 0.5 with 0.7 how many digits will be there in the multiplication after the decimal….obviously 2 because one number involves 5 but other doesn't involve even number.
Multiply 0.5 with 0.2 how many digits will be there in the multiplication after the decimal….now you will say 2 again its wrong because 0.1 and 0.10 is same so there is only 1 digit. So the right answer would be 1.

So whenever you have a 5 involved in the end of a number and even number at the end of the other number then number of digits will be less by 1 from original.

Please KUDOS me if this helps explain better.


I would like to add there that if the last two digits are divisible by 4, then the number of digits would be less by 2 from the original.

Had it been product of
95.75 and .02564 = 24.5503

OR

95.75 and .02544 = 24.3588

Same test applies on both the numbers. 75 is a multiple of 25 & 64 is multiple of 4; so resultant product will always give 100 (2 zero's at the end)

We require to focus on last 2 digits of both numbers to have a airtight answer :)


I think the products are not correct, it would be 2.45503 & 2.43588. But the logic in perfect thanks, u got +1 Kudos
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Re: How many digits will be there to the right of the decimal  [#permalink]

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New post 20 Dec 2015, 10:09
It's not difficult, as soon as you multiply you see that the last number is a 0.
If it was not a 0, then the answer would be 7.
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Re: How many digits will be there to the right of the decimal  [#permalink]

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New post 20 Dec 2015, 21:23
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At first, it seems 7, but a quick glance shows that 75*54 gives one 0 at the end.

So, the correct answer is 6
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Re: How many digits will be there to the right of the decimal  [#permalink]

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New post 15 Aug 2016, 03:41
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Re: How many digits will be there to the right of the decimal  [#permalink]

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New post 16 Aug 2016, 06:58
vinnik wrote:
How many digits will be there to the right of the decimal point in the product of 95.75 and .02554 ?

A. 5
B. 6
C. 7
D. 8
E. None of these

I thought it was easy. I don't really need to multiply the numbers, but i was wrong. Please share your thoughts on this question.

Thanks & Regards
Vinni



available 0 = 10^2*10^5
now you have to check for 2 and 5 from 2554 and 9575. if you notice 54, last 2 digit 2554, you know it's not divisible by 4 so only 2 is available so only one 10 = 7-1 =6
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Re: How many digits will be there to the right of the decimal  [#permalink]

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New post 27 Sep 2018, 01:44
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Re: How many digits will be there to the right of the decimal &nbs [#permalink] 27 Sep 2018, 01:44
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